A researcher is interested in finding a 98% confidence interval for the mean number of times perday that college students text. The study included 97 students who averaged 26.5 texts per day.The standard deviation was 19.7 texts.a. To compute the confidence interval use a ? distribution.b. With 98% confidence the population mean number of texts per day is betweentexts.andc. If many groups of 97 randomly selected members are studied, then a different confidenceinterval would be produced from each group. Aboutpercent of these confidenceintervals will contain the true population number of texts per day and aboutnot contain the true population mean number of texts per day.percent will

Given Mean =X-bar=26.5 Standard deviations=S=19.7 n=97

Answered: A researcher is interested in finding a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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10)The superintendent of a golf course believes that the mean score for professional golfers on his course is above 72. He randomly samples the scores of 40 professional golfers from the last tournament. Here are the scores. 69 67 69 71 75 78 70 71 72 74 72 76 69 76 70 77 78 79 72 71 75 75 75 78 71 64 71 68 72 71 73 72 73 71 71 75 72 72 78 75 Construct a 95% confidence interval for the mean score for all professional golfers on this course. (note: ∑xi=∑xi= 2908, ∑x2=∑x2= 211,850)
According to the College Board, scores on the math section of the SAT Reasoning college entrance test for the class of 2010 had a mean of 516 and a standard deviation of 116. Assume that they are roughly normal.One of the quartiles of the scores from the math section of the SAT Reasoning test is 438. The other quartile is _______.
When a population has less variability, for the same margin of error and confidence level, the confidence interval becomes a. larger b. smaller c. of unchanged size
A researcher is interested in finding a 90% confidence interval for the mean number of times per day that college students text. The study included 97 students who averaged 25.5 texts per day. The standard deviation was 20.5 texts. Round answers to 3 decimal places where possible. b. With 90% confidence the population mean number of texts per day is between ______ and _______ texts. c. If many groups of 97 randomly selected members are studied, then a different confidence interval would be produced from each group. About _______ percent of these confidence intervals will contain the true population number of texts per day and about ___________ percent will not contain the true population mean number of texts per day.
do B AND C
A study is conducted to compare the performance of students with more than one personal electronic gadget and those with only one. A number of them were taken as subjects for the study. The mean grades of these students and the standard deviations are shown below: For one gadget: The mean is 83, standard deviation is 12, and sample size is 7. For more than one gadget: The mean is 79, standard deviation is 13, and sample size is 5. Is it possible to conclude that there is no significant difference in the mean grades of the two types of students at a 95% confidence interval? Note: This is a two-tailed test. Also take note that this is finding the difference between two population means.
A study of 4 bolts of carpet showed that their average length was 76.2 yards and the sample standard deviation was 5.6 yards. Which of the following is the 80% confidence interval for the mean length per bolt of carpet? O A. 75.8 to 76.6 O B. 72.62 to 79.78 O C. 71.61 to 80.79 D. 75.40 to 77.00
tion. Use this information to construct the 90% and 95% confidence intervals fc of the confidence intervals. ce of a certain stock was $123.13. Assume the population standard deviation is
create a 90% confidence interval for the following data: x = 25 n = 100
A study is done to determine if students in the California state university (CSU) system take longer to graduate, on average, than students enrolled in private universities using the significant level of 5%. One hundred students from both the California state university system and private universities are surveyed. Suppose that from years of research, it is known that the population standard deviations are 1.5811 years for CSU and 1 year for private universities. The following data are collected. The California state university system students took on average 4.5 years with a standard deviation of 0.8. The private university students took on average 4.1 years with a standard deviation of 0.3. What is the decision rule of rejecting the null hypothesis
Toby wants to know the average price of new cars at a particular dealearship. He randomly selects a sample of 31 cars and finds that the average price to be $19500$19500 with a standard deviation of $1640$1640. What is the 95% confidence interval for the mean price of cars at this particular dealership? With 95% confidence, we can say the true population mean price of cars at this dealership is between $____ and _____$ .Round to the nearest dollar
In a random sample of 38 criminals convicted of a certain crime, it was determined that the mean length of sentencing was 61 months, with a standard deviation of 8 months. Construct and interpret a 95% confidence interval for the mean length of sentencing for this crime. Select the correct choice below and fill in the answer boxes to complete your choice.(Use ascending order. Round to one decimal place as needed.) A. 95% of the sentences for the crime are between ____ and ____ months. B. There is a 95% probability that the mean length of sentencing for the crime is between ____ and ____ months. C. We can be 95% confident that the mean length of sentencing for the crime is between

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