A researcher is interested in finding a 95% confidence interval for the mean number of times per day thatcollege students text. The study included 115 students who averaged 36.8 texts per day. The standarddeviation was 22.5 texts. Round answers to 3 decimal places where possible.a. With 95% confidence the population mean number of texts per day is betweenandtexts.b. If many groups of 115 randomly selected members are studied, then a different confidence intervalwould be produced from each group. Aboutpercent of these confidence intervals will containpercent will not contain the truethe true population number of texts per day and aboutpopulation mean number of texts per day.

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Answered: A researcher is interested in finding a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A researcher is interested in finding a 98% confidence interval for the mean number of times per day that college students text. The study included 134 students who averaged 25.9 texts per day. The standard deviation was 21.5 texts. Round answers to 4 decimal places where possible. a. To compute the confidence interval use a ? distribution. b. With 98% confidence the population mean number of texts per day is between ?and ?texts. c. If many groups of 134 randomly selected members are studied, then a different confidence interval would be produced from each group. About ? percent of these confidence intervals will contain the true population number of texts per day and about ?percent will not contain the true population mean number of texts per day.
3. Given the following GPA for 4 students: 2, 3, 3, 4. Age of students are: 10, 11,12, 15. There are 10,000 total students. Average GPA: Unknown, StandardDeviation of GPA: 0.02 and it’s Normal.a. Find the mean and standard deviation for GPA.b. Calculate a 95% confidence interval for the populations mean GPA.c. Use Correlation formula to find r between GPA and Age.d. Find Regression Line Equation.e. If a student’s age is 13, what is the corresponding GPA?
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
In a survey, 28 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $45 and standard deviation of $14. Construct a confidence interval at a 99% confidence level. Give your answers to one decimal place. ________+________
4. on paper. random sample of 130 human body temperatures had a mean 98.25 degree and astandard deviation of 0.73 degree. Construct a 99% confidence interval for the average body temperature ofhealthy people.
Find the following. Enter your answer rounded to at least two decimals. z a/2 for the 97% confidence interval
A professor was curious about her students' grade point averages. She took a random sample of 15 students and found a mean GPA of 3.01 with a standard deviation of 0.534. Which of the following formulas gives a 99% confidence interval for the mean GPA of the professor's students?
The following data represent a random sample of five measurements from a normally distributed population: 7,4,2,5,7 a. Find 90% confidence interval for u. b. Find a 99% confidence interval for u.
A survey of 32,782 adults in 2004 indicated that 24.6% of adults were current smokers. A similar study conducted in 1995 of 40,000 adults indicated that 29.7% were current smokers. a. Find and interpret a point estimate of the difference between the proportion of current smokers in 1995, and the proportion of current smokers in 2004. b. A 95% confidence interval for the true difference is (-0.058,-0.045). Interpret. c. What assumptions must you make for the confidence interval i part b to be valid? (…) a. Find a point estimate of the difference between the proportion of current smokers in 1995 and the proportion of current smokers in 2004. (Round to three decimal places as needed.)
create a 90% confidence interval for the following data: x = 25 n = 100
The following is the number of hours of sleep obtained by eight college freshmen. Use the data to find a 92% confidence interval for the true mean number of hours of sleep by college freshmen. 7.5 8.0 6.5 24 8.5 6.5 7.0 7.5

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