A researcher is interested in constructing a 99% confidence interval for the proportion of Alzheimer patients living in nursing homes who exhibit temporary memory improvement while being visited by their loved ones. 920 of the 1356 randomly observed Alzheimer patients did show temporary memory improvement. Round your answers to two decimal places. A. With 99% confidence the proportion of all Alzheimer patients living in nursing homes who exhibit temporary memory improvement while being visited by their loved ones is between  and  . B. If many groups of 1356 randomly selected Alzheimer patients living in nursing homes are observed while being visited by their loved ones, then a different confidence interval would be produced for each group. About  percent of these confidence intervals will contain the true population proportion of all Alzheimer patients living in nursing homes that exhibit temporary memory improvement while being visited by their loved ones and about  percent will not contain the true population proportion.

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.