A researcher crosses mice with apricot eyes and long tails, and the F1 progeny were recovered in the following numbers and phenotypic classes: F1: 21 apricot, short : 30 brown, long : 19 brown, short : 110 apricot, long You know the genes encoding these traits are autosomal, completely dominant and assort independently. You want to use a chi-square test to analyse these results. a) What is your null hypothesis for the chi-square test? b) You obtain a value of 11.33 for the chi-square test. What conclusion can you make from the results of the chi-square test? c) Give the expected number of individuals in the "apricot, long" class. d) Making use of the appropriate genetic convention for naming alleles, give the genotype of any of the progeny in the "apricot, long" class. P df 0.995 0.975 0.9 0.5 0.1 0.05* 0.025 0.01 0.005 0.000 0.000 0.016 0.455 2.706 3.841 5.024 6.635 7.879 0.010 0.051 0.211 1.386 4.605 5.991 7.378 9.210 10.597 0.072 0.216 0.584 2.366 6.251 7.815 9.348 11.345 12.838 4 0.207 0.484 1.064 3.357 7.779 9.488 11.143 13.277 14.860
A researcher crosses mice with apricot eyes and long tails, and the F1 progeny were recovered in the following numbers and phenotypic classes: F1: 21 apricot, short : 30 brown, long : 19 brown, short : 110 apricot, long You know the genes encoding these traits are autosomal, completely dominant and assort independently. You want to use a chi-square test to analyse these results. a) What is your null hypothesis for the chi-square test? b) You obtain a value of 11.33 for the chi-square test. What conclusion can you make from the results of the chi-square test? c) Give the expected number of individuals in the "apricot, long" class. d) Making use of the appropriate genetic convention for naming alleles, give the genotype of any of the progeny in the "apricot, long" class. P df 0.995 0.975 0.9 0.5 0.1 0.05* 0.025 0.01 0.005 0.000 0.000 0.016 0.455 2.706 3.841 5.024 6.635 7.879 0.010 0.051 0.211 1.386 4.605 5.991 7.378 9.210 10.597 0.072 0.216 0.584 2.366 6.251 7.815 9.348 11.345 12.838 4 0.207 0.484 1.064 3.357 7.779 9.488 11.143 13.277 14.860
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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Transcribed Image Text:A researcher crosses mice with apricot eyes and long tails, and the F1 progeny were recovered in the following numbers and phenotypic classes:
F1: 21 apricot, short : 30 brown, long : 19 brown, short : 110 apricot, long
You know the genes encoding these traits are autosomal, completely dominant and assort independently. You want to use a chi-square test to analyse these
results.
a) What is your null hypothesis for the chi-square test?
b) You obtain a value of 11.33 for the chi-square test. What conclusion can you make from the results of the chi-square test?
c) Give the expected number of individuals in the "apricot, long" class.
d) Making use of the appropriate genetic convention for naming alleles, give the genotype of any of the progeny in the "apricot, long" class.
P
df
0.995
0.975
0.9
0.5
0.1
0.05*
0.025
0.01
0.005
1
0.000
0.000
0.016
0.455
2.706
3.841
5.024
6.635
7.879
2
0.010
0.051
0.211
1.386
4.605
5.991
7.378
9.210
10.597
0.072
0.216
0.584
2.366
6.251
7.815
9.348
11.345
12.838
4
0.207
0.484
1.064
3.357
7.779
9.488
11.143
13.277
14.860
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