A researcher conducts an experiment to examine the relationship between the weight gain (wtgn, gm) of chickens, whose diets had been supplemented by different amounts of lysine, and the amount of lysine (gm) ingested. A random sample of 12 chicks was selected for the study. The R output is given below. Call: lm(formula = wtgn ~ lysine, data = lys) Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) 12.57 1.18 10.65 8.9e-07 lysine 35.48 6.89 5.15 0.00043 Residual standard error: 1.02 on 10 degrees of freedom Multiple R-squared: 0.726, Adjusted R-squared: 0.699 F-statistic: 26.5 on 1 and 10 DF, p-value: 0.000432 95% CI 95% PI fit lwr upr fit lwr upr 16.8 15.9 17.8 16.8 14.4 19.3 The results for a test of Ho:β1=0Ho:β1=0 versus Ha:β1≠0Ha:β1≠0 show that: (pick one) a. the null hypothesis can be rejected because t=5.15, p=0.00043. b. the null hypothesis cannot be rejected because t=10.65, p=8.9e-07. c. the null hypothesis cannot be rejected because t=5.15, p=0.00043. d. the null hypothesis can be rejected because t=10.65, p=8.9e-07.
A researcher conducts an experiment to examine the relationship between the weight gain (wtgn, gm) of chickens, whose diets had been supplemented by different amounts of lysine, and the amount of lysine (gm) ingested. A random sample of 12 chicks was selected for the study. The R output is given below.
Call:
lm(formula = wtgn ~ lysine, data = lys)
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 12.57 1.18 10.65 8.9e-07
lysine 35.48 6.89 5.15 0.00043
Residual standard error: 1.02 on 10 degrees of freedom
Multiple R-squared: 0.726, Adjusted R-squared: 0.699
F-statistic: 26.5 on 1 and 10 DF, p-value: 0.000432
95% CI 95% PI
fit lwr upr fit lwr upr
16.8 15.9 17.8 16.8 14.4 19.3
The results for a test of Ho:β1=0Ho:β1=0 versus Ha:β1≠0Ha:β1≠0 show that: (pick one)
a. the null hypothesis can be rejected because t=5.15, p=0.00043.
|
b. the null hypothesis cannot be rejected because t=10.65, p=8.9e-07. |
|
c. the null hypothesis cannot be rejected because t=5.15, p=0.00043. |
d. the null hypothesis can be rejected because t=10.65, p=8.9e-07.
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
