A researcher claims that the number of homicide crimes by season is uniformly distributed. To test this claim, you randomly select 1,199 homicides from a recent year and record the season when each happened. The table shows the results. At α = 0.05, test the researcher's claim. Which hypothesis is the claim? Но Ha Calculate the test statistic. Season Determine the P-value. Spring Summer Fall Winter Frequency, f 305 310 296 288 x² = .950 (Round to three decimal places as needed.) P-value= .813 (Round to three decimal places as needed.)

MATLAB: An Introduction with Applications
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Chapter1: Starting With Matlab
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Could you please IN DETAIL explain this portion? I have gotten this far on my own but I am genuinely lost and would like an explanation. Like think of me as someone who has only taken Alegebra 1 and you're going to simplify this but do it in detail that I can understand. If you're using a chart, graph, table, excel, etc. INCLUDE IT in your explanation. Also, could you please write this down and NOT useing Bartleby's step 1, step 2, step 3, etc.? It doesn't sow me the full explanatin and I usually have to re-ask the question and that takes away from what questions I have left.

**Chi-Square Goodness-of-Fit Test Example**

A researcher claims that the number of homicide crimes by season is uniformly distributed. To test this claim, you randomly select 1,199 homicides from a recent year and record the season when each happened. The table shows the results. At a significance level of α = 0.05, test the researcher's claim.

**Data Table:**

| Season | Frequency, f |
|--------|--------------|
| Spring | 305          |
| Summer | 310          |
| Fall   | 296          |
| Winter | 288          |

**Hypothesis Testing:**

- **Which hypothesis is the claim?**
  - \( H_0 \) (Null Hypothesis) is selected.

- **Calculate the test statistic.**
  - \( \chi^2 = 0.950 \) (rounded to three decimal places as needed)

- **Determine the P-value.**
  - P-value = 0.813 (rounded to three decimal places as needed)

**Decision:**

Decide whether to reject or fail to reject the null hypothesis and interpret the decision in the context of the original claim.

- Statement: \(\_\_\_\_\_\) \( H_0 \). There \(\_\_\_\) enough evidence at the 5% level of significance to reject the claim that the distribution of the number of homicide crimes by season \(\_\_\_\).

**Conclusion:**

- Since the P-value is greater than 0.05, we do not reject \( H_0 \).
- There is not enough evidence to reject the claim that the distribution of the number of homicide crimes by season is uniform.
Transcribed Image Text:**Chi-Square Goodness-of-Fit Test Example** A researcher claims that the number of homicide crimes by season is uniformly distributed. To test this claim, you randomly select 1,199 homicides from a recent year and record the season when each happened. The table shows the results. At a significance level of α = 0.05, test the researcher's claim. **Data Table:** | Season | Frequency, f | |--------|--------------| | Spring | 305 | | Summer | 310 | | Fall | 296 | | Winter | 288 | **Hypothesis Testing:** - **Which hypothesis is the claim?** - \( H_0 \) (Null Hypothesis) is selected. - **Calculate the test statistic.** - \( \chi^2 = 0.950 \) (rounded to three decimal places as needed) - **Determine the P-value.** - P-value = 0.813 (rounded to three decimal places as needed) **Decision:** Decide whether to reject or fail to reject the null hypothesis and interpret the decision in the context of the original claim. - Statement: \(\_\_\_\_\_\) \( H_0 \). There \(\_\_\_\) enough evidence at the 5% level of significance to reject the claim that the distribution of the number of homicide crimes by season \(\_\_\_\). **Conclusion:** - Since the P-value is greater than 0.05, we do not reject \( H_0 \). - There is not enough evidence to reject the claim that the distribution of the number of homicide crimes by season is uniform.
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