**Transcription:**---A researcher claims that a post-lunch nap decreases the amount of time it takes males to sprint 20 meters after a night with only 4 hours of sleep. The table shows the amounts of time (in seconds) it took for 10 males to sprint 20 meters after a night with only 4 hours of sleep when they did not take a post-lunch nap and when they did take a post-lunch nap. At α = 0.10, is there enough evidence to support the researcher's claim? Assume the samples are random and dependent, and the population is normally distributed. Complete parts (a) through (c) below.| Male | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 ||------|---|---|---|---|---|---|---|---|---|----|| **Sprint time (without nap)** | 4.01 | 4.06 | 4.01 | 3.97 | 3.94 | 3.94 | 3.93 | 3.92 | 3.89 | 3.87 || **Sprint time (with nap)** | 3.91 | 3.99 | 3.85 | 3.92 | 3.92 | 3.87 | 3.89 | 3.81 | 3.79 | 3.74 |(a) Identify the claim and state $ H_0 $ and $ H_a $.What is the claim?A. A post-lunch nap decreases the amount of time it takes males to sprint 20 meters. B. A night with only 4 hours of sleep increases the amount of time it takes males to sprint 20 meters. C. A post-lunch nap increases the amount of time it takes males to sprint 20 meters. D. A night with only 4 hours of sleep decreases the amount of time it takes males to sprint 20 meters.Let $ d $ be the hypothesized mean of the difference in the sprint times (without nap – with nap). What are $ H_0 $ and $ H_a $?A. $ H_0: \mu_d \le 0 $ $ H_a: \mu_d > 0 $ B

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Description: **Transcription:**---A researcher claims that a post-lunch nap decreases the amount of time it takes males to sprint 20 meters after a night with only 4 hours of sleep. The table shows the amounts of time (in seconds) it took for 10 males to sprint

(a) Here, the claim of the test the post-lunch nap decreases the amount of time it takes males to…

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A researcher claims that a post-lunch nap decreases the amount of time it takes males to sprint 20 meters after a night with only 4 hours of sleep. The table shows the amounts of time (in seconds) it took for 10 males to sprint 20 meters after a only 4 hours of sleep when they did not take a post-lunch nap and when they did take a post-lunch nap. At a= 0.10, is there enough evidence to support the researcher's daim? Assume the samples are random and dependent, and the population is normally distributed. Complete parts (a) through (e) below. ra night with Maie Sprint time (without hap) Sprint time (with nap) 3.91 3.99 3.95 3.92 3.92 3.79 3.82 3.89 3.81 3.79 12 3 4 56 7 89 10 4.04 4.06 4.01 3.97 3.94 3.91 3.97 4.02 3.93 3.91

A researcher claims that a post-lunch nap decreases the amount of time it takes males to sprint 20 meters after a night with only 4 hours of sleep. The table shows the amounts of time (in seconds) it took for 10 males to sprint 20 meters after a only 4 hours of sleep when they did not take a post-lunch nap and when they did take a post-lunch nap. At a= 0.10, is there enough evidence to support the researcher's daim? Assume the samples are random and dependent, and the population is normally distributed. Complete parts (a) through (e) below. ra night with Maie Sprint time (without hap) Sprint time (with nap) 3.91 3.99 3.95 3.92 3.92 3.79 3.82 3.89 3.81 3.79 12 3 4 56 7 89 10 4.04 4.06 4.01 3.97 3.94 3.91 3.97 4.02 3.93 3.91

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Concept explainers

Contingency Table

A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear relationship between two variables. A contingency table is indeed a type of frequency distribution table that displays two variables at the same time.

Binomial Distribution

Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.

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Question

**Transcription:**

---

A researcher claims that a post-lunch nap decreases the amount of time it takes males to sprint 20 meters after a night with only 4 hours of sleep. The table shows the amounts of time (in seconds) it took for 10 males to sprint 20 meters after a night with only 4 hours of sleep when they did not take a post-lunch nap and when they did take a post-lunch nap. At α = 0.10, is there enough evidence to support the researcher's claim? Assume the samples are random and dependent, and the population is normally distributed. Complete parts (a) through (c) below.

| Male | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
|------|---|---|---|---|---|---|---|---|---|----|
| **Sprint time (without nap)** | 4.01 | 4.06 | 4.01 | 3.97 | 3.94 | 3.94 | 3.93 | 3.92 | 3.89 | 3.87 |
| **Sprint time (with nap)** | 3.91 | 3.99 | 3.85 | 3.92 | 3.92 | 3.87 | 3.89 | 3.81 | 3.79 | 3.74 |

(a) Identify the claim and state $ H_0 $ and $ H_a $.

What is the claim?

A. A post-lunch nap decreases the amount of time it takes males to sprint 20 meters.
B. A night with only 4 hours of sleep increases the amount of time it takes males to sprint 20 meters.
C. A post-lunch nap increases the amount of time it takes males to sprint 20 meters.
D. A night with only 4 hours of sleep decreases the amount of time it takes males to sprint 20 meters.

Let $ d $ be the hypothesized mean of the difference in the sprint times (without nap – with nap). What are $ H_0 $ and $ H_a $?

A. $ H_0: \mu_d \le 0 $
$ H_a: \mu_d > 0 $

B

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