### Hypothesis Testing ProblemA researcher claims that 45% of U.S. adults think that the IRS is not aggressive enough in pursuing people who cheat on their taxes. You believe the true percentage is more than 45%. To test this, you take a simple random sample of 300 U.S. adults and find that 162 of them say the IRS is not aggressive enough. Test at 0.01 significance.**Instructions:**- **Round to the fourth**#### Hypotheses- **Null Hypothesis (\(H_0\)):** [Select] [Select]- **Alternative Hypothesis (\(H_A\)):** [Select] [Select]#### Calculations- **How many successes were there?** [Input Box]- **Test Statistic:** [Input Box]- **P-value:** [Input Box]#### Conclusion- **Did something significant happen?** [Select]- **Select the Decision Rule:** [Select]- **There [Select] enough evidence to conclude**- [Select an answer]The task involves filling in the blanks and selecting the appropriate options from dropdown menus to complete the hypothesis test.

The hypothesized proportion is It is believed that the true proportion is greater than the hypothesized proportion.The sample size is The number of people who say that the IRS is not aggressive enough is The level of significance is Null Hypothesis : The proportion of U.S. adults who think that the IRS is not aggressive enough in pursuing people who cheat on their taxes is 0.45.Alternative Hypothesis : The proportion of U.S. adults who think that the IRS is not aggressive enough in pursuing people who cheat on their taxes is more than 0.45.Mathematically,In this context, “success” is defined as finding a person who says the IRS is not aggressive enough. The number of successes in the sample is the number of people who responded this way. From the provided information, there were 162 successes. This is because 162 out of the 300 individuals in the sample said that the IRS is not aggressive enough in pursuing people who cheat on their taxes.The sample proportion is thus calculated as:Now, the test statistic can be calculated as:Hence the value of the test statistic is 3.1334.Since the alternative hypothesis is of the form , the test is right-tailed.Thus the P-value is calculated as:The value of the probability is calculated using the formula "=1-NORMSDIST(3.1334)" in Excel as follows:Yes, something significant did happen. The P-value of 0.0009 is less than the significance level of 0.01, indicating that the observed data is highly unlikely under the null hypothesis.The decision rule is, if the P-value is less than the significance level (0.01), reject the null hypothesis.Mathematically, In this case, .Clearly, , so the null hypothesis is rejected.Therefore, there is enough evidence to conclude that the true proportion of U.S. adults who think the IRS is not aggressive enough in pursuing people who cheat on their taxes is more than 45%.The hypotheses are:There were 162 successes.Test statistic: 3.1334P-value: 0.0009Yes, something significant did happen. The p-value of 0.0009 is less than the significance level of 0.01, indicating that the observed data is highly unlikely under the null hypothesis.The decision rule is, if the p-value is less than the significance level (0.01), reject the null hypothesis.Therefore, there is enough evidence to conclude that the true proportion of U.S. adults who think the IRS is not aggressive enough in pursuing people who cheat on their taxes is more than 45%.