A researcher affirms that the average time that students in the morning and afternoon shiftsof an elementary school use social networks are the same. Therefore, independent randomsamples of 15 students from the morning shift and 17 from the afternoon shift are taken andthe following times in minutes are observed:Morning 132 131 132 133 134 128 134 132 134 128 132 133 128 132 142Evening 125 126 126 134 126 129 137 125 129 140 132 123 137 127 133 131 138Assuming normality in these data, perform:a)A hypothesis test with a significance level of 0.10 forb) The hypothesis test of the researcher's statement with a significance level of 0.10,considering the result of the hypothesis test in the previous section.a

The provided information is as follows:The total number of students from the morning shift is .The…

Answered: A researcher affirms that the average…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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A recent study indicates that people tend to select video game avatars with characteristics like those of their creators (Bélisle & Bodur, 2010). Participants who had created avatars for a virtual community game completed a questionnaire about their personalities. An independent group of viewers examined the avatars and recorded their impressions of the avatars. One personality characteristic considered was introverted/extroverted. The following frequency distribution of personalities for participants and the avatars they created. Is there a significant relationship between the personalities of the participants and the personalities of their avatars? Test with α = .05.
According to the U.S. Department of Transportation’s Air Travel Consumer Report, the nation’s 12 largest airlines recorded an on-time arrival percentage of 77.4% in 2001. Of interest is to estimate the mean delay time for the 22.6% of all flights that did not arrive on time during 2013. A simple random sample of 28 late arriving flights was selected, and the mean delay time of this sample of 28 flights was 14.2 minutes, with a sample standard deviation of s= 6.4 minutes. Use this information to calculate and interpret a 98% confidence interval for the mean delay time for all flights that did not arrive on time during 2013.
A samll town installed a Blue streetlights, in part, to help reduce crime in particular areas. The city collected the number of property crimes along nine randomly selected streets in the month before and after the Blue light installation, and claims that crime has been reduced.The number of crime data is shown in the table. No before Blue Light After Blue Light 1 17 14 2 25 20 3 10 14 4 14 12 5 16 8 6 34 35 7 32 27 8 21 18 9 14 12 a. Specify the competing hypotheses to test the s,all town's claim.b. Calculate the value of the relevant test statistic and find the critical value at the 5% significance level.c. Does the evidence support the small town's claim at the 5% significance level?
Two microprocessors are compared on a sample of six benchmark codes to determine whether there is a difference in speed. The times (in seconds) used by each processor on each code are given in the following table. Code 4 6 Processor A 27.2 18.1 27.2 19.7 24.5 22.1 Processor B 24.1 19.3 26.8 20.1 27.6 29.8 Can you conclude that the mean speeds of the two processors differ?
3. Some sports psychologists believe that an athlete's motivation is related to how many hours they will devote to training in a 2-week period. To see if this is true, a sports trainer measures the motivation (M) and training hours (TH) of a random sample of 8 Olympic-class athletes and obtains the following data: M TH 57 40 74 46 42 38 48 36 75 54 62 42 665 76 550 69 25 a) Is there a significant correlation between M and TH in this sample (a≤.05)? (8 points) b) If another athlete obtained an M score of 70, what would his or her predicted TH score be and what are the 90% bounds to the error of this prediction? (10 points)
The data to the right represent the number of chocolate chips per cookie in a random sample of a name brand and a store brand. Complete parts (a) to (c) below. Full data set D Name Brand Store Brand 20 23 26 24 28 19 21 27 33 28 33 15 29 22 25 17 22 21 22 30 20 26 23 24 25 27 ... (a) Draw side-by-side boxplots for each brand of cookie. Label the boxplots "N" for the name brand and "S" for the store brand. Choose the correct answer below. OA. OB. OC. N- N- N- 10 20 30 40 10 20 30 40 10 20 30 40 (b) Does there appear to be a difference in the number of chips per cookie? O A. Yes. The store brand appears to have more chips per cookie. O B. No. There appears to be no difference in the number of chips per cookie. O C. Yes. The name brand appears to have more chips per cookie. O D. There is insufficient information to draw a conclusion. (c) Does one brand have a more consistent number of chips per cookie? O A. No. Both brands have roughly the same number of chips per cookie. O B. Yes. The…
The National Football League (NFL) records a variety of performance data for individuals and teams. To investigate the importance of passing on the percentage of games won by a team, the following data show the average number of passing yards per attempt (Yds/Att) and the percentage of games won (WinPct) for a random sample of 10 NFL teams for the 2011 season (NFL website). Team Yds/Att WinPct 5.7 26 Arizona Cardinals Atlanta Falcons Carolina Panthers 7.6 67 7.3 52 6.9 51 Chicago Bears Dallas Cowboys 5.1 17 8.6 82 New England Patriots Philadelphia Eagles Seattle Seahawks 5.3 21 6.6 41 St. Louis Rams 6.5 41 Tampa Bay Buccaneers. 6.1 38 a. Choose the correct a scatter diagram with the number of passing yards per attempt on the horizontal axis and the percentage of games won on the vertical axis. B. A. WinPct WinPct 80 DD J F1 70- 60- 50+ -40- 30 20- F2 80 F3 000 000 F4 F5 80- -70 60- 50- 40- 30- 20- S F6 ● - F7 DII F8 F9 F10 () F11 <))) F12 A
A study is done to determine if students in the California state university (CSU) system take longer to graduate, on average, than students enrolled in private universities using the significant level of 5%. One hundred students from both the California state university system and private universities are surveyed. Suppose that from years of research, it is known that the population standard deviations are 1.5811 years for CSU and 1 year for private universities. The following data are collected. The California state university system students took on average 4.5 years with a standard deviation of 0.8. The private university students took on average 4.1 years with a standard deviation of 0.3. What is the decision rule of rejecting the null hypothesis
A study from 2014 found that adults in the US spend an average of 11 hours per day watching, reading, listening to or simply interacting with media. Researchers at UCLA suspect students spend less time engaging media. They grouped UCLA students by class section, randomly selected 20 class sections, and administered a survey to each student in those randomly selected class sections. The following data represents the mean time (in hours) per day spent engaging media for each of the randomly selected classes: 9.5 11.5 6.0 7.5 8 9.5 10.5 11 12 8.2 5 9.5 8.2 9.3 10.8 11 13 8.6 9.5 10.5 What would be the calculator steps to find standard deviaton, rounded to 3 decimal places?
A cross-sectional study is conducted to investigate cardiovascular disease (CVD) risk factors among a sample of patients seeking medical care at one of three local hospitals. A total of 500500 patients are enrolled. Based on the following data, we would like to determine if there is a significant association between the family history of CVD and the enrollment site. Enrollment Site Family History of CVD Hospital 1 Hospital 2 Hospital 3 Total Yes 34 8 58 100 No 104 72 224 400 Total 138 80 282 500 Given: The value of the test statistic is χ2= 6.912 Use α=0.1 as the level of significance. The superintendent of Hospital 2 performed the Goodness of Fit Test to test whether 25% of the patients go to Hospital 1, 15% of the patients go to Hospital 2 and 60% of the patients go to Hospital 3. Given: The superintendent found that the pp-value for the test is 0.25091 Let: p1=p1= be the proportion of patients at Hospital 1 p2=p2= be the proportion of patients at…

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