A research team interested in the proportion of patients at a local hospital that are admitted to the emergency room without any form of healthcare insurance. Supposed to team hypothesizes that the proportion of these patients was 19%, and conducted a sample of 298 participants to find that 109 were without any insurance at 95% confidence. What was the power of the tests conducted?

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A research team interested in the proportion of patients at a local hospital that are admitted to the emergency room without any form of healthcare insurance. Supposed to team hypothesizes that the proportion of these patients was 19%, and conducted a sample of 298 participants to find that 109 were without any insurance at 95% confidence. What was the power of the tests conducted?

Expert Solution
Step 1

Given
Sample size = n =298
number of patients with out insurance be X =109
The proportion of patients with out insurance =109298=0.3658

Null hypothesis Ho: p = 0.19
Alternate hypothesis Ha: p  0.19

As the alternate hypothesis has ≠ , the hypothesis test is two tailed test.
The test statistic is calculated as shown below
Z=p^-pp(1-p)nZ=0.3658-0.190.19(1-0.19)298=7.734

 

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