A research organization wanted to estimate the average number of hours a college student sleeps per night during the school year. After randomly sampling 150 college​ students, the research organization determined the following​ 95% confidence​ interval: (7.1,7.5)​ hours/night. What is the value of the average number of hours slept per night during the school year for these 150 college​ students?

Q: In a survey of 2279 ​adults, 729 say they believe in UFOs. Construct a 90% confidence…

A:

Q: There are 3000 beads of various colors in a jar. In a sample of 125 beads, 40% were red. Calculate…

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Q: When Mendel conducted his famous genetics experiment with peas, one sample of offspring consisted of…

A: Obtain the 95% confidence interval estimate of the percentage of yellow peas. The 95% confidence…

Q: A survey was constructed that asked 1017 people how many books they had read in the past year.…

A: The following information has been given: The sample size is n=1017. The sample mean is x¯=10.5. The…

Q: According to a Harris Interactive survey of 2401 adults conducted in April 2009, 25% of adults do…

A:

Q: The following sample data are from a normal population: 10, 8, 12, 15, 13, 11, 6, 5. What is the…

A: Given data is10,8,12,15,13,11,6,5sample size(n)=8sample mean(x¯)=10standard…

Q: A poll for a statewide election has a margin of error of 2.14 percentage points. How many voters…

A: From the provided information,Margin of error (E) = 0.0214Confidence level = 99%

Q: In a survey of 2344 ​adults, 715 say they believe in

A: Given that there are 2344 adults and 715 say they believe in UFOs. Consider the sample proportion,…

Q: In a survey of 2000 adults in a recent​ year, 708 made a New​ Year's resolution to eat healthier.…

A: Confidence interval for population proportion is given by, p^ +- z* √(pq/n) At 90% z = 1.645 At 95%…

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: find the margin of error for a sample mean, given n=16, s=4, Xbar=17. for a 95% confidence interval.

A: The margin of error for sample mean is given by,

Q: The internal auditing staff of a local manufacturing company performs a sample audit each quarter to…

A:

Q: A poll reported 38% support for a statewide election with a margin of error of 1.36 percentage…

A: Proportion of voters who supports for a statewide election Margin of error Confidence level

Q: A survey asked, "How many tattoos do you currently have on your body?" Of the 1223 males surveyed,…

A: From the given information, 1223 males surveyed, 188 responded that they had at least one tattoo.…

Q: Using the 99% level of confidence, what is the confidence interval for proportion of students…

A: Let X be the random variable such number of students attending home football games. X = 750 N: Total…

Q: In a survey of 2002 adults in a recent​ year, 701 made a New​ Year's resolution to eat healthier.…

A: Given:

Q: Out of 200 people sampled, 42 had kids. Based on this, construct a 95% confidence interval for the…

A: For 95% confidence intervalα=1-CI=1-0.95=0.05So, zα2=z0.052=z0.025=1.96

Q: a recent study of 100 people in Burlingame found that 19 were obese.  Find the 90% confidence…

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Q: A researcher was interested in knowing how many people in the city supported a new tax. She sampled…

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Q: In 2017, the CDC administered the Youth Risk Behavior Survey (YRBS) to a random sample of 14,795…

A: The random variable cyber bullied follows normal distribution. The sample size is 14795. The number…

Q: 99% confidence interval for the proportion of the high school students who have been cyberbullied,…

A: Given that Sample size n = 14795 Number of high school students who have cyberbullied, X = 2219 The…

Q: A large container contains colored beads. A simple random sample of beads yielded 107 red beads and…

A:

Q: In 2017, the CDC administered the Youth Risk Behavior Survey (YRBS) to a random sample of 14,795…

A: We have given that,  Favorable cases (X) = 2219 and sample size   (n) = 14795. Then,  We will find…

Q: What proportion of the sample reported that they had been cyberbullied?

A: Givensample size(n)=14795No.of respondents say yes they had been cyberbullied(x1) = 2219No.of…

Q: A random variance survey of 495 adults found that 59 had diabetes. which of the following is a 98%…

A:

Q: What is the value of Z for this confidence interval?

A: Given,sample size(n)=14795no.of people who said yes=2219no.of people who said no =12576

Q: A​ 95% confidence interval for the proportion of U.S. adults who subscribe to some sort of streaming…

A: In the above question, we are given,  a confidence interval is

Q: qualities as options, one of which is "communicator", as the most important quality for an effective…

A: It is given that  Favourable cases, X = 121 Sample size, n = 275 Sample proportion, p^ = X/n…

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: when 282 college students are randomly selected and surveyed, it is found that 109 own a car. find a…

A: It is given that sample size (n) is 282 and x is 109.

Q: Out of 300 people sampled, 171 had kids. Based on this, construct a 95% confidence interval for the…

A:

Q: A survey asked, "How many tattoos do you currently have on your body?" Of the 1232 males surveyed,…

A: Given that: Total number of males surveyed, n1=1232 Number of male respondent with at least one…

Q: A poll reported 60% support for a statewide election with a margin of error of 3.35  percentage…

A: The question is about sample size estimationGiven :Proportion of voters who supports for a statewide…

Q: igh school soccer league there are a total of 256 players.

A: Given that Total players in high school soccer league (n) = 256 players The mean height of the…

Q: andom sample of 1200 high school freshmen was taken and it was found that 559 of them were reading…

A: The population proportion (p) will be proportion of high school freshman who reads at or above their…

Q: A survey of 300 women shoppers found that 17% of them shop on impulse. What is the 80% confidence…

A: From the provided information,A survey of 300 women shoppers found that 17% of them shop on impulse.…

Q: Out of 300 people sampled, 279 had kids. Based on this, construct a 90% confidence interval for the…

A:

Q: From a lake, an unknown proportion of fish have been tagged.  You collect a sample of 100 fish taken…

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Q: An arborist is interested in determining the mean diameter (in centimeters) of mature white oak…

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Q: The manager at Bell’s Gym wants to know the proportion of members who use the Cardio Machines. A…

A: DETAILED SOLUTION IS PROVIDED BELOWExplanation:

Q: UC Berkeley randomly selects 100 students to represent them on the World Universities Congress next…

A: UC Berkeley randomly selects 100 students to represent them on the World Universities Congress next…

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.