A research conducted by SSTA022 Class representative at the University of Limpopo indicates that running increases the lifespan among African men. The mean lifespan of 31 African men runners was 34.0% more than the mean lifespan of 31 inactive African men, with variances reported to be 110.25% and 104.04%, respectively. Assuming the populations to be approximately normally distributed with equal variances. ii) Construct a 95% confidence interval for μ₁ −μ₂.
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 44 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with…
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Q: test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with garlic…
A: Given that Sample size n =43 Sample mean =5.7 Standard deviation =16.1
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with…
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Q: and after the treatment. The changes (before-after) in their levels of LDL cholesterol (in mg/dL)…
A: Given n=sample size=49, Sd=17.1, mean difference x̄d=2.8 Level of significance ɑ=0.05
Q: In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 44 subjects were treated with…
A: The sample size is 44, the mean is 4.9 and the standard deviation is 15.7.
Q: In a test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with…
A: Given Information: Sample size n=43 Sample mean x¯d=3.2 Sample standard deviation sd=17.9 Confidence…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with…
A: given data sample size (n) = 42sample mean ( xd¯ ) = 5.5sample standard deviation (sd) =17.490% ci…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 44 subjects were treated with…
A: From the provided information, Sample size (n) = 44 Sample mean (x̄) = 4.4 Sample standard deviation…
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Q: Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with…
A: sample size(n)=49Mean()=3.6standard deviation(s)=17.7confidence level=90%
Q: Two groups of individuals were compared with respect to a high carbohydrate low- fat diet (LF) and a…
A: Given: x¯ 1=47.3x¯2=19.3n1=12n2=13s1=28.3s2= 25.8
Q: In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with…
A: From the provided information, Sample size (n) = 43 Sample mean (x̄) = 3.1 Sample standard deviation…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with…
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A: Given: n1 = 20 n2 = 20 X1 = 18.02 X2 = 24.31 σ1 = 3 σ2 = 3 Formula Used: Upper confidence bound =…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with…
A: Obtain the 99% confidence interval estimate of the mean net change in LDL cholesterols after the…
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- A psychologist wants to test whether there is any difference in puzzle-solving abilities between boys and girls. Independent samples of eleven boys and seven girls were chosen at random. The boys took a mean of 37 minutes to solve a certain puzzle, with a standard deviation of 4.8 minutes. The girls took a mean of 35 minutes to solve the same puzzle, with a standard deviation of 4.5 minutes. Assume that the two populations of completion times are normally distributed, and that the population variances are equal. Can we conclude, at the 0.10 level of significance, that the mean puzzle-solving times for boys, μ1 is greater than the mean puzzle-solving times for girls, μ2? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in the table. a. State the null hypothesis H0 and the alternative hypothesis H1. b. Find the value of the test statistic. (Round to three or more decimal…In a test of the effectiveness of garlic for lowering cholesterol, 44 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before−after) in their levels of LDL cholesterol (in mg/dL) have a mean of 5.7 and a standard deviation of 17.7. Construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? What is the confidence interval estimate of the population mean μ? ____mg/dL<μ<_____mg/dLIn a test of the effectiveness of garlic for lowering cholesterol, 47 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before−after) in their levels of LDL cholesterol (in mg/dL) have a mean of 2.8 and a standard deviation of 16.3. Construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol?
- In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.9 and a standard deviation of 15.3. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? | mg/dL < µIn a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.6 and a standard deviation of 17.5. Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? mg/dL <µ< mg/dL (Round to two decimal places as needed.)In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before−after) in their levels of LDL cholesterol (in mg/dL) have a mean of 5.3 and a standard deviation of 17.4. Construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? . What is the confidence interval estimate of the population mean μ? enter your response here mg/dL<μ<enter your response here mg/dL (Round to two decimal places as needed.)Two groups of individuals were compared with respect to a high carbohydrate low-fat diet (LF) and a high-fat low carbohydrate diet (LC). Mood was assessed using a total mood disturbance score where a lower score is associated with a less negative mood. Assuming that the random samples come from independent normal distributions with a common but unknown variance, construct a 95% confidence interval for the difference between the two population means, LC less LF. Group LC LF 28+18.56 28±8.96 28±22.37 28+22.30 n 12 13 mean 47.3 19.3 standard deviation 28.3 25.8Two groups of individuals were compared with respect to a high carbohydrate low- fat diet (LF) and a high-fat low carbohydrate diet (LC). Mood was assessed using a total mood disturbance score where a lower score is associated with a less negative mood. Assuming that the random samples come from independent normal distributions with a common but unknown variance, construct a 95% confidence interval for the difference between the two population means, LC less LF. Group LC LF 28+22.37 28+18.56 28+22.30 28±8.96 n 12 13 mean 47.3 19.3 standard deviation 28.3 25.8In a test of the effectiveness of garlic for lowering cholesterol, 47 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.7 and a standard deviation of 18.2. Construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean p? Question Viewer mg/dL < p< mg/dL (Round to two decimal places as needed.) What does the confidence interval suggest about the effectiveness of the treatment? O A. The confidence interval limits do not…In a test of the effectiveness of garlic for lowering cholesterol, 45 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before−after)in their levels of LDL cholesterol (in mg/dL) have a mean of 4.6 and a standard deviation of 16.3. Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? What is the confidence interval estimate of the population mean μ? ______ mg/dL<μ<_____ mg/dL (Round to two decimal places as needed.) What does the confidence interval suggest about the effectiveness of the treatment? A. The confidence interval limits contain 0, suggesting that the garlic treatment did not affect the LDL cholesterol levels. B. The confidence interval limits contain 0, suggesting that the garlic treatment…In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before- after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.1 and a standard deviation of 15.8. Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean µ? mg/dL mg/dL<µ< (Round to two decimal places as needed.) What does the confidence interval suggest about the effectiveness of the treatment? O A. The confidence interval limits contain 0, suggesting that the…A researcher decides to measure anxiety in group of bullies and a group of bystanders using a 23-item, 3 point anxiety scale. Assume scores on the anxiety scales are normally distributed and the variance among the group of bullies and bystanders are the same. A group of 30 bullies scores an average of 21.5 with a sample standard deviation of 10 on the anxiety scale. A group of 27 bystanders scored an average of 25.8 with a sample standard deviation of 8 on the anxiety scale. You do not have any presupposed assumptions whether bullies or bystanders will be more anxious so you formulate the null and alternative hypothesis based on that.
