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a) Remember this readers-writers synchronization problem from BUX and the reference book. 3. do { wait (mutex); read.count++3B if (read_count == 1) wait (rw.mutex); signal (mutex); .. /* reading is performed */ do { wait (rw_mutex); wait (mutex); read_count--; if (read.count == 0) signal (rw_mutex); signal (mutex); } while (true); /* writing is performed */ signal (rw.mutex); } while (true); Figure 5.11 The structure of a writer process. Figure 5.12 The structure of a reader process. This solution solves the critical section problem. However, there is a starvation issue here for the writer process. If there is a steady stream of reader processes in the ready queue, the writer process may starve and may not be able to write. We hope you can solve this starvation issue by applying one restriction in the code. The restriction is that if the writer was waiting for a reader, then that reader cannot read again before the writer completes writing. If than reader reading when the writer was waiting, this more one were restriction applies to all those readers. Update the reader and writer code to implement this restriction.

a) Remember this readers-writers synchronization problem from BUX and the reference book. 3. do { wait (mutex); read.count++3B if (read_count == 1) wait (rw.mutex); signal (mutex); .. /* reading is performed */ do { wait (rw_mutex); wait (mutex); read_count--; if (read.count == 0) signal (rw_mutex); signal (mutex); } while (true); /* writing is performed */ signal (rw.mutex); } while (true); Figure 5.11 The structure of a writer process. Figure 5.12 The structure of a reader process. This solution solves the critical section problem. However, there is a starvation issue here for the writer process. If there is a steady stream of reader processes in the ready queue, the writer process may starve and may not be able to write. We hope you can solve this starvation issue by applying one restriction in the code. The restriction is that if the writer was waiting for a reader, then that reader cannot read again before the writer completes writing. If than reader reading when the writer was waiting, this more one were restriction applies to all those readers. Update the reader and writer code to implement this restriction.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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3. a) Remember this readers-writers synchronization problem from BUX and the reference book. do { wait(mutex); read_count++; if (read_count == 1) wait(rw_mutex); signal(mutex); /* reading is performed */ do { wait(rw_mutex); wait (mutex); read_count--; if (read_count == 0) signal (rw_mutex); signal (mutex); } while (true); /* writing is performed */ signal (rw_mutex); } while (true); Figure 5.11 The structure of a writer process. Figure 5.12 The structure of a reader process. This solution solves the critical section problem. However, there is a starvation issue here for the writer process. If there is a steady stream of reader processes in the ready queue, the writer process may starve and may not be able to write. We hope you can solve this starvation issue by applying one restriction in the code. The restriction is that if the writer was waiting for a reader, then that reader cannot read again before the writer completes writing. If more restriction applies to all those readers. Update the reader and writer code to implement this restriction. than reader were reading when the writer was waiting, this one HINTS: You do not need any additional mutex for this but need to use both
Transcribed Image Text:3. a) Remember this readers-writers synchronization problem from BUX and the reference book. do { wait(mutex); read_count++; if (read_count == 1) wait(rw_mutex); signal(mutex); /* reading is performed */ do { wait(rw_mutex); wait (mutex); read_count--; if (read_count == 0) signal (rw_mutex); signal (mutex); } while (true); /* writing is performed */ signal (rw_mutex); } while (true); Figure 5.11 The structure of a writer process. Figure 5.12 The structure of a reader process. This solution solves the critical section problem. However, there is a starvation issue here for the writer process. If there is a steady stream of reader processes in the ready queue, the writer process may starve and may not be able to write. We hope you can solve this starvation issue by applying one restriction in the code. The restriction is that if the writer was waiting for a reader, then that reader cannot read again before the writer completes writing. If more restriction applies to all those readers. Update the reader and writer code to implement this restriction. than reader were reading when the writer was waiting, this one HINTS: You do not need any additional mutex for this but need to use both
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