A refrigerator uses refrigerant-134a as the working fluid and operates on an ideal vapor- compression refrigeration cycle between 0.14 and 0.8 MPa. If the mass flow rate of the refrigerant is 0.05 kg/s. determine (a) the rate of heat removal from the refrigerated space and the power input to the compressor. (b) the rate of heat rejection to the environment. and (¢) the COP of the refrigerator. P;=0.14 MPa — hv=239.19 kl/kg 5=0.94467 kI P,=0.8 MPa — hL=275.40 ki/kg P3=0.8 MPa — h=95.48 kl/kg

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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Q1/A refrigerator uses refrigerant-134a as the working fluid and operates on an ideal vapor- compression refrigeration cycle between 0.14 and 0.8 MPa. If the mass flow rate of the refrigerant is 0.05 kg/s. determine (a) the rate of heat removal from the refrigerated space and the power input to the compressor. (b) the rate of heat rejection to the environment. and (¢) the COP of the refrigerator. P;=0.14 MPa — hv=239.19 kl/kg 5=0.94467 kI P,=0.8 MPa — hL=275.40 ki/kg P3=0.8 MPa — h=95.48 kl/kg
Q1/A refrigerator uses refrigerant-134a as the working fluid and operates on an ideal vapor-
compression refrigeration cycle between 0.14 and 0.8 MPa. If the mass flow rate of the refrigerant
is 0.05 kg/s, detenmine (a) the rate of heat removal from the refiigerated space and the power input
to the compressor, (b) the rate of heat rejection to the environment, and (c) the COP of the
refrigerator.
P1 = 0.14 MPa → hv= 239.19 kJ/kg
s= 0.94467 kJ/kg-K
P2=0.8 MPa
- hL= 275.40 kJ/kg
P3 = 0.8 MPa –h= 95.48 kJ/kg
Transcribed Image Text:Q1/A refrigerator uses refrigerant-134a as the working fluid and operates on an ideal vapor- compression refrigeration cycle between 0.14 and 0.8 MPa. If the mass flow rate of the refrigerant is 0.05 kg/s, detenmine (a) the rate of heat removal from the refiigerated space and the power input to the compressor, (b) the rate of heat rejection to the environment, and (c) the COP of the refrigerator. P1 = 0.14 MPa → hv= 239.19 kJ/kg s= 0.94467 kJ/kg-K P2=0.8 MPa - hL= 275.40 kJ/kg P3 = 0.8 MPa –h= 95.48 kJ/kg
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