AA refrigeration unit at a restaurant is supposed to be kept at 40°F. An inspector would like to test the hypothesesHo: μ = 40 versus H: 40 where u = the true mean temperature for all times of the day. A 98% confidenceinterval based upon a random sample of 40 temperatures is 40.5 degrees to 42.1 degrees. Using the interval, whatdecision should be made?O The null hypothesis should be rejected at the α = 0.01 level.The null hypothesis should be rejected at the α = 0.02 level.O The null hypothesis should not be rejected at the α = 0.05 level.O The null hypothesis should not be rejected at the a = 0.10 level.

The following information has been provided: The hypothesized mean is μ=40. Null and Alternative…

Answered: A refrigeration unit at a restaurant is…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A century ago, the average height of adult women in the United States was 63 inches. Researchers believe that the average might be greater today. A random sample of 40 adult women was selected from the population. The sample had mean 64.2 inches and standard deviation 2.9 inches. Assuming all conditions for inference are met, the researchers will perform an appropriate hypothesis test to investigate their belief. Which of the following is the correct test statistic for the hypothesis test? A t = 63-64.2 2.9 63-64.2 2.9 t 3= 63-64.2 29 40 64.2-63 t 3= 2.9 64.2-63 t = 2.9 US 1 DELL 么 & %24 %23 || E.
A random sample of 78 measurements was selected from a population with ?=2.76σ=2.76. The sample mean was 122.5. Calculate a 99% confidence interval for ?
A random sample of 46 adult coyotes from Northern Minnesota showed the average age to be sample mean of 2.05 years. The population standard deviation is known to be o = 1.13 years. However, it is thought that the average age of coyotes is u = 1.75 years. Test to see if the coyotes in Northern Minnesota live longer than the national average of 1.75 years. Use 0.03 level of significance. What are the hypotheses? A: Ho µ= 1.75 years vs HA µ> 1.75 years B: Ho µ= 1.75 years vs HA H 2.05 years D: Ho µ = 2.05 years vs HA u< 2.05 years O A D O O
The accompanying data are measured body temperatures of adults at 12 AM on a certain day. Use the Wilcoxon signed-ranks test to test the claim that the median is equal to 98.6°F. Use a 0.05 significance level. Click the icon to view the body temperature data. Determine the null and alternative hypotheses. Ho: The median body temperature is H₁: The median body temperature is (Type integers or decimals. Do not round.) Determine the P-value. The P-value is (Round to three decimal places as needed.) Determine the proper conclusion. Ho. There is ▼ ✔ evidence at the 0.05 significance level to warrant rejection of the claim that the median body temperature is C 98.6°F. Body Temperature Data 98.1 97.7 98.7 98.1 98.9 97.7 98.5 98.7 98.1 98.1 98.1 97.9 97.3 98.3 98.0 98.1 98.4 99.1 97.9 96.9 97.2 98.2 97.9 98.9 97.5 98.1 97.3 98.1 98.5 98.5 96.9 98.5 98.1 99.3 97.7 98.3 98.9 97.8 98.1 98.0 98.6 97.3 98.4 98.6 98 7 99.0 97.3 97.5 98.0 98.1 98.6 98.7 98.7 98.7 99.2 97.7 97.7 98.5 97.6 99.4 97.6…
The National Assessment of Educational Progress (NAEP) includes a mathematical test for eighth-grade students. Scores on the test range from 0 to 500. Suppose that you give the NAEP test to an SRS of 2500 eighth-graders from a large population in which the scores have mean u = 282 and standard deviation o = 110. The mean x will vary if you take repeated samples. Suppose that we computed a 90% confidence interval for u. Which is true? This 90% confidence interval could have either a smaller or a larger margin of error than the 95% confidence interval. This varies from sample to sample. This 90% confidence interval would have a smaller margin of error than the 95% confidence interval. This 90% confidence interval would have a larger margin of error than the 95% confidence interval. This 90% confidence interval would have the margin of error as the 95% confidence interval.
A simple random sample of size 10 has a mean of 65.0 and a sample standard deviation of 8.0. A student would like to test the null hypothesis, ?0:?=70.0H0:μ=70.0, against the alternative, ?1:?<70.0H1:μ<70.0. Construct a confidence interval corresponding to this test at significance level ?=10%α=10%. Give your answer precise to two decimal places. lower limit = upper limit =
In order to construct a confidence interval for the population variance, a random sample of n observations is drawn from a normal population. Use this information to find x²a/2, df and x²1-a/2, df under the following scenarios. (Round your answers to 3 decimal places. You may find it useful to reference the appropriate table: chi-square table or Ftable) X²al2,df a. A 95% confidence level with n = 9. b. A 95% confidence level with n = 40. c. A 99% confidence level with n = 9. d. A 99% confidence level with n = 40. X²1-a/2,df
please check this. The recidivism rate for convicted sex offenders is 14%. A warden suspects that this percent is different if the sex offender is also a drug addict. Of the 324 convicted sex offenders who were also drug addicts, 32 of them became repeat offenders. What can be concluded at the αα = 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: Ho: (please enter a decimal) H1: (Please enter a decimal) The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly different from 14% at αα = 0.05, so there is statistically significant evidence to conclude that the population proportion of convicted sex offender drug addicts who become repeat offenders…
Under what circumstances is a t statistic used instead of a z-score for a hypothesis test? Justin wants to know whether a commonly prescribed drug does improve the attention span of students with attention deficit disorder (ADD). He knows that the mean attention span for students with ADD who are not taking the drug is 2.3 minutes long. His sample of 12 students taking the drug yielded a mean of 4.6 minutes. Justin can find no information regarding σx , so he calculated s2x =1.96. Determine the critical region using a one-tailed test with alpha = .05. Conduct the hypothesis test (Do the math and compare the t-critical and t-obtained values). State your conclusions in terms of H0 (Should you reject the H0 or fail to reject/accept the H0). Based on your analysis, is there a relationship between the drug and attention span?
BIG Corporation advertises that its light bulbs have a mean lifetime, u, of 3000 hours. Suppose that we have reason to doubt this claim and decide to do a statistical test of the claim. We choose a random sample of light bulbs manufactured by BIG and find that the mean lifetime for this sample is 3160 hours and that the sample standard deviation of the lifetimes is 600 hours. Based on this information, answer the questions below. What are the null hypothesis (H.) and the alternative hypothesis (H,) that should be used for the test? Ho: u is ? H: u is ? In the context of this test, what is a Type I error? A Type I error is ? v the hypothesis that u is? when, in fact, u is ? Suppose that we decide to reject the null hypothesis. What sort of error might we be making? ?
The time needed to find a parking space is normally distributed with a mean of 20 minutes and a standard deviation of 5.18 minutes. 90% of the time, it takes less than how many minutes to find a parking space?

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