A rectangular parallelepiped with a square based = 0.260 m on a side and a height h = 0.120 m has a mass m = 6.50 kg. While this object is floating in water, oil with a mass density e, = 710 kg/m3 carefully poured on top of the water until the situation looks like that shown in the figure. Determine the height of the parallelepiped in the water. m

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Chapter1: Units, Trigonometry. And Vectors
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The image depicts a problem involving a rectangular parallelepiped floating in a liquid mixture of oil and water. The parallelepiped is described as having a square base with a side length \( d = 0.260 \, \text{m} \) and a height \( h = 0.120 \, \text{m} \). The mass of the parallelepiped is \( m = 6.50 \, \text{kg} \). 

In the situation illustrated, the object is floating, with oil having a mass density \( \rho_o = 710 \, \text{kg/m}^3 \) poured on top of the water until the state displayed in the figure is achieved. The task is to determine the height of the parallelepiped submerged in the water.

**Diagram Description:**
- The diagram shows a beaker filled with two layers of liquid: the bottom layer is water, and the top layer is oil.
- The parallelepiped is partially submerged, with its lower part in the water and the upper part extending into the oil.
- Several dimensions and notations are indicated:
  - \( d \): The length of the sides of the square base.
  - \( h \): The total height of the parallelepiped.
  - \( h_w \): The height of the parallelepiped submerged in the water.
  - \( h_o \): The height of the parallelepiped submerged in the oil.

**Objective:**
Determine \( h_w \), the height of the parallelepiped submerged in the water layer.
Transcribed Image Text:The image depicts a problem involving a rectangular parallelepiped floating in a liquid mixture of oil and water. The parallelepiped is described as having a square base with a side length \( d = 0.260 \, \text{m} \) and a height \( h = 0.120 \, \text{m} \). The mass of the parallelepiped is \( m = 6.50 \, \text{kg} \). In the situation illustrated, the object is floating, with oil having a mass density \( \rho_o = 710 \, \text{kg/m}^3 \) poured on top of the water until the state displayed in the figure is achieved. The task is to determine the height of the parallelepiped submerged in the water. **Diagram Description:** - The diagram shows a beaker filled with two layers of liquid: the bottom layer is water, and the top layer is oil. - The parallelepiped is partially submerged, with its lower part in the water and the upper part extending into the oil. - Several dimensions and notations are indicated: - \( d \): The length of the sides of the square base. - \( h \): The total height of the parallelepiped. - \( h_w \): The height of the parallelepiped submerged in the water. - \( h_o \): The height of the parallelepiped submerged in the oil. **Objective:** Determine \( h_w \), the height of the parallelepiped submerged in the water layer.
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