A record is played by spinning the record so that a circular groove in the vinyl slides under the stylus. Suppose that a record turns at a rate of 33 1/3 rev. min, the groove being played is at a radius of 10.0 cm and the bumps in the grove are uniformly separated by 1.75 mm. At what rate (hits per second) do the bumps hit the stylus? Enter units as hertz (Hz). You will need v=rω ω is in rad/s and 1rev = 2 pi rad.
A record is played by spinning the record so that a circular groove in the vinyl slides under the stylus. Suppose that a record turns at a rate of 33 1/3 rev. min, the groove being played is at a radius of 10.0 cm and the bumps in the grove are uniformly separated by 1.75 mm. At what rate (hits per second) do the bumps hit the stylus? Enter units as hertz (Hz). You will need v=rω ω is in rad/s and 1rev = 2 pi rad.
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A record is played by spinning the record so that a circular groove in the vinyl slides under the stylus. Suppose that a record turns at a rate of 33 1/3 rev. min, the groove being played is at a radius of 10.0 cm and the bumps in the grove are uniformly separated by 1.75 mm. At what rate (hits per second) do the bumps hit the stylus? Enter units as hertz (Hz). You will need v=rω ω is in rad/s and 1rev = 2 pi rad.
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