A recent study at a local college claimed that the proportion, \( p \), of students who commute more than fifteen miles to school is no more than 20%. If a random sample of 270 students at this college is selected, and it is found that 71 commute more than fifteen miles to school, can we reject the college’s claim at the 0.01 level of significance?Perform a one-tailed test. Then fill in the table below.Carry your intermediate computations to at least three decimal places and round your answers as specified in the table. (If necessary, consult a list of formulas.)| | ||----------------------------|--------------------------------------|| **The null hypothesis:** | \( H_0: \) [Select appropriate symbol] || **The alternative hypothesis:** | \( H_1: \) [Select appropriate symbol] || **The type of test statistic:** | \( \) (Choose one: Z, t, Chi square, F) || **The value of the test statistic:** | [Value] (Round to at least three decimal places.) || **The critical value at the 0.01 level of significance:** | [Value] (Round to at least three decimal places.) |Can we reject the claim that the proportion of students who commute more than fifteen miles to school is no more than 20%?- [ ] Yes- [ ] No### Symbols and OperationsThe image includes a section with symbols and operations that can be used to fill in the hypothesis table:- Population mean (\(\mu\))- Population standard deviation (\(\sigma\))- Proportion (\(p\))- Sample mean (\(\bar{x}\))- Sample standard deviation (\(s\))- Sample proportion (\(\hat{p}\))Comparison operators (e.g., \(<\), \(\leq\), \(>\), \(\geq\), \(\neq\))### InteractionA dropdown menu for selecting the type of test statistic is visible, with options for Z, t, Chi square, and F tests. There is also a selection for entering symbols and values in the hypothesis section.

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A recent study at a local college claimed that the proportion, p, of students who commute more than fifteen miles to school is no more than 20%. If a ra sample of 270 students at this college is selected, and it is found that 71 commute more than fifteen miles to school, can we reject the college's claim at 0.01 level of significance? Perform a one-tailed test. Then fill in the table below. Carry your intermediate computations to at least three decimal places and round your answers as specified in the table. (If necessary, consult a list of for The null hypothesis: H, :0 The alternative hypothesis: H, :0 O=0 OSO The type of test statistic: v (Choose one O

A recent study at a local college claimed that the proportion, p, of students who commute more than fifteen miles to school is no more than 20%. If a ra sample of 270 students at this college is selected, and it is found that 71 commute more than fifteen miles to school, can we reject the college's claim at 0.01 level of significance? Perform a one-tailed test. Then fill in the table below. Carry your intermediate computations to at least three decimal places and round your answers as specified in the table. (If necessary, consult a list of for The null hypothesis: H, :0 The alternative hypothesis: H, :0 O=0 OSO The type of test statistic: v (Choose one O

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Q8. Please help.
An auditor for a local court system is tasked with comparing the rulings of two judges. The auditor needs to determine if Judge Hughes issues shorter sentences than Judge Wilson. The data below are the sentence lengths, in months, issued by each judge in their last twelve cases that dealt with operating a motor vehicle without a license. Test the claim that Judge Hughes issues shorter sentences than Judge Wilson for this particular type of case at the 0.05 level of significance. Let Judge Hughes' sentences be Population 1 and let Judge Wilson's sentences be Population 2. Assume that both populations are approximately normal and that the population variances are equal. Judge 24 12 12 30 Hughes 36 30 12 18 24 12 24 30 Judge 36 36 24 24 24 24 18 12 30 24 18 30 Wilson Copy Data Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places.
An auditor for a local court system is tasked with comparing the rulings of two judges. The auditor needs to determine if Judge Hughes issues shorter sentences than Judge Wilson. The data below are the sentence lengths, in months, issued by each judge in their last twelve cases that dealt with operating a motor vehicle without a license. Test the claim that Judge Hughes issues shorter sentences than Judge Wilson for this particular type of case at the 0.10 level of significance. Let Judge Hughes' sentences be Population 1 and let Judge Wilson's sentences be Population 2. Assume that both populations are approximately normal and that the population variances are equal. Judge Hughes 24 30 + Judge 18 18 36 30 Wilson 12 36 36 Copy Data Step 1 of 3: State the null and alternative hypotheses for the test. Fill in the blank below. Ho :μ₁ = 1₂ Ha: ₁ 12 24 M₂ 12 30 36 18 36 36 24 12
Suppose a study reported that the average person watched 3.34 hours of television per day. A random sample of 15 people gave the number of hours of television watched per day shown. At the 10% significance level, do the data provide sufficient evidence to conclude that the amount of television watched per day last year by the average person differed from the value reported in the study? (Note: x = 4.400 hours and s= 1.262 hours.) Set up the hypotheses for the one-mean t-test. HoiH Ha: H 2.3 4.0 4.5 4.9 5.0 4.5 3.3 2.0 5.7 5.9 6.2 3.8 5.9 3.9 4.1
The results: A. Are, or B. Are not significantly: A. High, or B. Low so there: A. is, or B. is not
A magazine provided results from a poll of 500 adults who were asked to identify their favorite pie. Among the 500 respondents, 13% chose chocolate pie, and the margin of error was given as ±4 percentage poits. Describe what is meant by the statement that "the margin of error was given as ±4 percentage points." (...) Choose the correct answer below. OA. The statement indicates that the study is only 4% confident that the true population percentage of people that prefer chocolate pie is exactly 13%. OB. The statement indicates that the study is 100% -4% = 96% confident that the true population percentage of people that prefer chocolate pie is 13%. OC. The statement indicates that the interval 13% ± 4% is likely to contain the true population percentage of people that prefer chocolate pie. D. The statement indicates that the true population percentage of people that prefer chocolate pie is in the interval 13% ± 4%.
Suppose IQ scores were obtained for 20 randomly selected sets of siblings. The 20 pairs of measurements yield x = 102.13, y = 101.35, r= 0.927, P-value = 0.000, and y = 2.05 + 0.97x, where x represents the IQ score of the older child. Find the best predicted value of y given that the older child has an IQ of 103? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. Critical Values of the Pearson Correlation Coefficient r The best predicted value of y is (Round to two decimal places as needed.) Critical Values of the Pearson Correlation Coefficient r a = 0.05 a = 0.01 NOTE: To test Ho: p=0 Jagainst H,: p#0, reject H, lif the absolute value of r is greater than the critical value in the table. 4. 0.950 0.990 0.878 0.959 6 0.811 0.917 0.754 0.875 8. 0.707 0.834 0.666 0.632 0.602 9 0.798 10 0.765 11 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 0.468 0.456 18 0.590 19 0.575…
Use the results from a survey of a simple random sample of 1064 adults. Among the 1064 respondents, 69% rated 13 themselves as above average drivers. We want to test the claim that more than 20 of adults rate themselves as above average drivers. Complete parts (a) through (e). A. No. Assuming quality of driving can be quantified, half of all adults must have driving quality less than or equal to the mean. B. Yes. Assuming quality of driving can be quantified, a distribution that is extremely skewed to the right would be the most promising scenario for more than this proportion of adults to have driving quality that is above the mean. C. Yes. Assuming quality of driving can be quantified, a distribution that is extremely skewed to the left would be the most promising scenario for more than this proportion of adults to have driving quality that is above the mean. O D. No. It is impossible to compare the quality of different adults' driving. b. If we use the same significance level to…
Is the proportion of wildfires caused by humans in the south higher than the proportion of wildfires caused by humans in the west? 429 of the 567 randomly selected wildfires looked at in the south were caused by humans while 396 of the 544 randomly selected wildfires looked at the west were caused by humans. What can be concluded at the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: Select an answer Select an answer v Select an answer | (please enter a decimal) Hj: Select an answer v Select an answer v Select an answer v (Please enter a decimal) c. The test statistic ? (please show your answer to 3 decimal places.) d. The p-value = e. The p-value is ? v a f. Based on this, we should Select an answer g. Thus, the final conclusion is that ... (Please show your answer to 4 decimal places.) the null hypothesis. O The results are statistically insignificant at a = 0.05, so there is statistically…
An auditor for a local court system is tasked with comparing the rulings of two judges. The auditor needs to determine if Judge Hughes issues shorter sentences than Judge Wilson. The data below are the sentence lengths, in months, issued by each judge in their last twelve cases that dealt with operating a motor vehicle without a license. Test the claim that Judge Hughes issues shorter sentences than Judge Wilson for this particular type of case at the 0.05 level of significance. Let Judge Hughes' sentences be Population 1 and let Judge Wilson's sentences be Population 2. Assume that both populations are approximately normal and that the population variances are equal. Judge 24 12 12 30 36 30 12 18 24 12 24 30 Hughes Judge Wilson 36 36 24 24 24 24 18 12 30 24 18 30 Step 3 of 3: Draw a conclusion and interpret the decision. Copy Data