< 10.2 5.2 x 10-4 Before (mol) Change (mol) After (mol) 0 -10.2 Calculate the maximum grams of product for the reaction described below by constructing a BCA table and determining the maximum grams of possible product. Complete Parts 1-2 before submitting your answer. Ca (PO )₂(s) + 3 H₂SO₂(aq) → 3 CaSO (s) + 2 H₂PO₂(aq) NEXT > A reaction occurs starting with 1.00 kg of Ca (PO), and 1.00 kg of H₂SO. Based on your knowledge of stoichiometry, set up the table below to determine the amounts of each reactant and product after the reaction goes to completion.. -5.2 x 10-4 1.0 Question 25 of 70 1 3.22 0.52 Ca (PO) (s) + 3 H₂SO₂(aq) 3 CaSO (s) + 2 H₂PO₂(aq) -1.0 -3.22 -0.52 2 3.22 × 10-³ 6.45 -3.22 x 10.³ -6.45 9.67 x 10.³ 9.67 Submit RESET -9.67 × 10-³ -9.67 +

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Stoichiometry and BCA Table Problem**

**Objective:**
Calculate the maximum grams of product for the reaction described by constructing a BCA (Before, Change, After) table and determining the maximum grams of possible product. Complete Parts 1-2 before submitting your answer.

**Chemical Reaction:**

\[ \text{Ca}_3(\text{PO}_4)_2(s) + 3 \text{H}_2\text{SO}_4(aq) \rightarrow 3 \text{CaSO}_4(s) + 2 \text{H}_3\text{PO}_4(aq) \]

**Instructions:**
A reaction occurs starting with 1.00 kg of \(\text{Ca}_3(\text{PO}_4)_2\) and 1.00 kg of \(\text{H}_2\text{SO}_4\). Based on your knowledge of stoichiometry, set up the table below to determine the amounts of each reactant and product after the reaction goes to completion.

**BCA Table Layout:**

\[
\begin{array}{c|cccc}
& \text{Ca}_3(\text{PO}_4)_2(s) & + & 3 \text{H}_2\text{SO}_4(aq) & \rightarrow 3 \text{CaSO}_4(s) + 2 \text{H}_3\text{PO}_4(aq) \\
\hline
\text{Before (mol)} & & & & \\
\text{Change (mol)} & & & & \\
\text{After (mol)} & & & & \\
\end{array}
\]

**Choices for Table Entries:**
- \(0\)
- \(1.0\)
- \(-1.0\)
- \(3.22 \times 10^{-3}\)
- \(-3.22 \times 10^{-3}\)
- \(9.67 \times 10^{-3}\)
- \(-9.67 \times 10^{-3}\)
- \(10.2\)
- \(-10.2\)
- \(3.22\)
- \(-3.22\)
- \(6.45\)
- \(-6.45\)
- \(9.67\)
- \(-9.67\)
- \(5.2
Transcribed Image Text:**Stoichiometry and BCA Table Problem** **Objective:** Calculate the maximum grams of product for the reaction described by constructing a BCA (Before, Change, After) table and determining the maximum grams of possible product. Complete Parts 1-2 before submitting your answer. **Chemical Reaction:** \[ \text{Ca}_3(\text{PO}_4)_2(s) + 3 \text{H}_2\text{SO}_4(aq) \rightarrow 3 \text{CaSO}_4(s) + 2 \text{H}_3\text{PO}_4(aq) \] **Instructions:** A reaction occurs starting with 1.00 kg of \(\text{Ca}_3(\text{PO}_4)_2\) and 1.00 kg of \(\text{H}_2\text{SO}_4\). Based on your knowledge of stoichiometry, set up the table below to determine the amounts of each reactant and product after the reaction goes to completion. **BCA Table Layout:** \[ \begin{array}{c|cccc} & \text{Ca}_3(\text{PO}_4)_2(s) & + & 3 \text{H}_2\text{SO}_4(aq) & \rightarrow 3 \text{CaSO}_4(s) + 2 \text{H}_3\text{PO}_4(aq) \\ \hline \text{Before (mol)} & & & & \\ \text{Change (mol)} & & & & \\ \text{After (mol)} & & & & \\ \end{array} \] **Choices for Table Entries:** - \(0\) - \(1.0\) - \(-1.0\) - \(3.22 \times 10^{-3}\) - \(-3.22 \times 10^{-3}\) - \(9.67 \times 10^{-3}\) - \(-9.67 \times 10^{-3}\) - \(10.2\) - \(-10.2\) - \(3.22\) - \(-3.22\) - \(6.45\) - \(-6.45\) - \(9.67\) - \(-9.67\) - \(5.2
### Chemistry Reaction Problem

**Question 25 of 70**

**Objective:**
Calculate the maximum grams of product for the reaction described below by constructing a BCA (Before, Change, After) table and determining the maximum grams of possible product. Complete Parts 1-2 before submitting your answer.

**Reaction Equation:**
\[ \text{Ca}_3(\text{PO}_4)_2 (s) + 3 \text{H}_2\text{SO}_4 (aq) \rightarrow 3 \text{CaSO}_4 (s) + 2 \text{H}_3\text{PO}_4 (aq) \]

**Instructions:**
- Based on the table from the previous step, determine the maximum number of grams of \(\text{CaSO}_4\) that can be produced.
  
**Input Field:**
\[ \text{mass}_{\text{CaSO}_4} = \_\_\_\_ \text{g} \]

**Data Values:**
Below are numerical data inputs or results possibly used in the BCA table calculations:
- \(0\)
- \(53.0\)
- \(167\)
- \(3.00 \times 10^3\)
- \(2.00 \times 10^3\)
- \(878\)
- \(1.32 \times 10^3\)
- \(70.8\)
- \(51.0\)
- \(632\)
- \(948\)

**Reset Button:**
- To clear the inputs or calculations, use the reset button.

This exercise involves applying stoichiometry and using the BCA table method to determine the maximum yield of calcium sulfate from a given chemical reaction.
Transcribed Image Text:### Chemistry Reaction Problem **Question 25 of 70** **Objective:** Calculate the maximum grams of product for the reaction described below by constructing a BCA (Before, Change, After) table and determining the maximum grams of possible product. Complete Parts 1-2 before submitting your answer. **Reaction Equation:** \[ \text{Ca}_3(\text{PO}_4)_2 (s) + 3 \text{H}_2\text{SO}_4 (aq) \rightarrow 3 \text{CaSO}_4 (s) + 2 \text{H}_3\text{PO}_4 (aq) \] **Instructions:** - Based on the table from the previous step, determine the maximum number of grams of \(\text{CaSO}_4\) that can be produced. **Input Field:** \[ \text{mass}_{\text{CaSO}_4} = \_\_\_\_ \text{g} \] **Data Values:** Below are numerical data inputs or results possibly used in the BCA table calculations: - \(0\) - \(53.0\) - \(167\) - \(3.00 \times 10^3\) - \(2.00 \times 10^3\) - \(878\) - \(1.32 \times 10^3\) - \(70.8\) - \(51.0\) - \(632\) - \(948\) **Reset Button:** - To clear the inputs or calculations, use the reset button. This exercise involves applying stoichiometry and using the BCA table method to determine the maximum yield of calcium sulfate from a given chemical reaction.
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