A ray that passes through the object nodal point of an optical system always
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what is the correct answer?
A ray that passes through the object nodal point of an optical system always
a) emerges from the optical system in a different direction as the incident ray
b) emerges from the optical system in the same direction as the incident ray
c) passes through the image focal point
d) passes through the image principal point
e) forms a virtual image
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- An object is placed in front of a lens which forms an image of the object. Which answer is correct A) If the image is real, then it is also upright. B) If the image is real, then it is also inverted. C) If the image is virtual, the lens must be a diverging lens. D) If the lens is convex, the image cannot be virtual. E) If the image is virtual, then it is also inverted.A converging lens of focal length 4 m produces a magnified image 2.4 times the size of the object. What is the object distance if the image is a) real? m b) virtual? m1 + So 1 Thin Lens Equation: Mr = Si Yo So Principle Ray: the ray from object to lens that is parallel to the principle (optical) axis will refract in a path that intersects the image focal point. Focal Ray: the ray from the object whose path is directed towards the object focal point will refract in a path parallel the principle (optical) axis. Central Ray: the ray from the object whose path is directed towards the center of the lens (intersection with the principle axis) will emerge from the lens undeflected. Conventions: Quantity Sign Positive (+) Negative (-) Object distance So Real object Virtual object Image distance Si Real image Virtual image Focal length f Converging lens Diverging Lens (opposite side of o,i) Object height Yo Erect object Inverted object Image height Yi Erect image Inverted image Magnification (transverse) MT Erect image Inverted image For the following lens configurations, carefully generate a ray trace diagram to locate the image graphically. Use the thin…
- A coin is 12 cm in front of a converging lens with focal length of magnitude 4.0 cm. Where is the image? A) 8.0 cm behind the lens B) 6.0 cm in front of the lens C) 6.0 cm behind the lens D) 4.0 cm in front of the lensA sharp image of a pencil that’s 25 cm away from your eye is formed on your retina. As you move the pencil farther away from your eye, what happens to the lens of your eye in order to form a sharp image on the retina? It gets less curved, increasing its focal length It gets less curved, decreasing its focal length It does not change It gets more curved, increasing its focal length It gets more curved, decreasing its focal lengthThe height of the image is -10 cm, which of the following is true? Question 10 options: it is upright it is virtual the magnification is positive it is inverted
- (numbers 8-9) An object is placed 12 cm from a diverging lens with a focal length of -6 cm. 8. How far is the image from the lens? 4 cm 4.5 cm 6 cm 8 cm 12 cm 9. The image is: real and smaller real and larger virtual and smaller virtual and larger none of the above answers are correctWhich of the following statements is true, if the upper half of the lens is covered? Assume that the object is not on the focal point of the lens. Object of Screen A. No image will be formed. OB. Half the image will be formed OC. Image of the entire object will be formed. Not enough information provided. ! No, that's not the correct answer.A) Please give examples of how to draw ray diagrams when the object is placed in front/behind the focal length for convex/concave mirrors B) Please give examples of how to draw ray diagrams when the object is placed in front/behind the focal length for coverging/diverging lenses C) Please give examples of how to draw ray diagrams when the object is placed in front/behind the focal length for systems involving 2 coverging and/or diverging lenses