A ray of monochromatic light of frequency 5.09x10 hertz is traveling from water into medium X. The angle of incidence in water is 45 and the angle of refraction in medium X is 29°, as show 12 (a) Normal 45° Water Medium X 29° Calculate the absolute index of refraction of X. Show all work, including the equation and substitution with units

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**Refraction of Monochromatic Light**

When a ray of monochromatic light with a frequency of 5.09 x 10^14 Hz travels from a medium of water into another medium (labeled as X), the light undergoes refraction at the interface of the two media. 

In this scenario:
- The angle of incidence in water is 45°.
- The angle of refraction in medium X is 29°, as depicted in the diagram below.

**Diagram of Refraction**:
- A ray of light is shown traveling from the water into medium X.
- The interface between the water and medium X is indicated by a horizontal line.
- The incident ray in the water medium forms an angle of 45° with the normal (a dashed vertical line).
- The refracted ray in medium X forms an angle of 29° with the normal.

**Objective**:
Calculate the absolute index of refraction of medium X. Be sure to show all work, including the equations and substitution with units.

**Formula and Calculation**:
To find the index of refraction of medium X, we use Snell's Law, which is defined as:

\[ n_1 \sin(\theta_1) = n_2 \sin(\theta_2) \]

In this equation:
- \( n_1 \) is the index of refraction of the first medium (water).
- \( \theta_1 \) is the angle of incidence in the first medium (45°).
- \( n_2 \) is the index of refraction of the second medium (medium X).
- \( \theta_2 \) is the angle of refraction in the second medium (29°).

Given:
- The index of refraction of water, \( n_1 \), is approximately 1.33.

We rearrange the formula to solve for \( n_2 \) (index of refraction of medium X):

\[ n_2 = \frac{n_1 \sin(\theta_1)}{\sin(\theta_2)} \]

Substitute the known values into the equation:

\[ n_2 = \frac{1.33 \sin(45°)}{\sin(29°)} \]

Using the sine values:

\[ \sin(45°) \approx 0.707 \]
\[ \sin(29°) \approx 0.484 \]

Now, substitute these values:

\[ n_
Transcribed Image Text:**Refraction of Monochromatic Light** When a ray of monochromatic light with a frequency of 5.09 x 10^14 Hz travels from a medium of water into another medium (labeled as X), the light undergoes refraction at the interface of the two media. In this scenario: - The angle of incidence in water is 45°. - The angle of refraction in medium X is 29°, as depicted in the diagram below. **Diagram of Refraction**: - A ray of light is shown traveling from the water into medium X. - The interface between the water and medium X is indicated by a horizontal line. - The incident ray in the water medium forms an angle of 45° with the normal (a dashed vertical line). - The refracted ray in medium X forms an angle of 29° with the normal. **Objective**: Calculate the absolute index of refraction of medium X. Be sure to show all work, including the equations and substitution with units. **Formula and Calculation**: To find the index of refraction of medium X, we use Snell's Law, which is defined as: \[ n_1 \sin(\theta_1) = n_2 \sin(\theta_2) \] In this equation: - \( n_1 \) is the index of refraction of the first medium (water). - \( \theta_1 \) is the angle of incidence in the first medium (45°). - \( n_2 \) is the index of refraction of the second medium (medium X). - \( \theta_2 \) is the angle of refraction in the second medium (29°). Given: - The index of refraction of water, \( n_1 \), is approximately 1.33. We rearrange the formula to solve for \( n_2 \) (index of refraction of medium X): \[ n_2 = \frac{n_1 \sin(\theta_1)}{\sin(\theta_2)} \] Substitute the known values into the equation: \[ n_2 = \frac{1.33 \sin(45°)}{\sin(29°)} \] Using the sine values: \[ \sin(45°) \approx 0.707 \] \[ \sin(29°) \approx 0.484 \] Now, substitute these values: \[ n_
**Question:**
(b) Based on your calculation from 3B.39, what material could Medium X possibly be made of?

**Answer:**
*Provide your answer in the space below.*
Transcribed Image Text:**Question:** (b) Based on your calculation from 3B.39, what material could Medium X possibly be made of? **Answer:** *Provide your answer in the space below.*
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