A ray of light enters from air to water and then into glass as shown in the diagram. Find the angle of refraction in glass. (n. = 1.33, n water 1.50) (33°) %3D 'glass 35° air water glass 3/siny = 1.33/1 x 1.50/1.33 =
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A ray of light enters from air to water and then into glass as shown in the diagram. Find the angle of refraction in glass. (nwater= 1.33, nglass= 1.50) (33o)
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![**Problem 7: Refraction through Different Mediums**
A ray of light enters from air to water and then into glass as shown in the diagram. Find the angle of refraction in glass.
- Refractive index of water \((n_{\text{water}} = 1.33)\).
- Refractive index of glass \((n_{\text{glass}} = 1.50)\).
- Incident angle in air is \(35^\circ\).
**Diagram Explanation:**
The diagram consists of three horizontal layers representing different mediums: air, water, and glass.
- The light ray enters from the air into the water at an angle of \(35^\circ\) with respect to the normal (vertical dotted line).
- The ray then continues from the water into the glass.
The task is to calculate the angle of refraction when the light enters the glass.
**Calculation:**
Use Snell's Law:
\[
\sin 33^\circ / \sin v = \frac{1.33}{1} \times \frac{1.50}{1.33}
\]
Where:
- \(33^\circ\) is the angle of refraction from air to water given in the problem.
Solve the equation to find \(v\), the angle of refraction in the glass.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F233cd45f-bb9a-4103-93a3-4df508ac34fb%2F9a7bd62c-d501-4790-9788-5f5da2de9d59%2Fqlp582_processed.png&w=3840&q=75)
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