a randomly selected sample of 2237 US adults, 1754 identified themselves as people who use the Internet regularly while the ther 483 indicated that they do not use the Internet regularly. In addition to Internet use, participants were asked if they agree rith the statement "most people can be trusted." The results show that 807 of the Internet users agree with this statement, while 30 of the non-users agree. Find a 90% confidence interval for the difference in the two proportions, p, - PN, where p, is the proportion for the internet users vho agree with the statement and py is the proportion for the non-internet users who agree with the statement. Round your answers to three decimal places. The 90% confidence interval is to 0.237

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Author:Amos Gilat
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In a randomly selected sample of 2237 US adults, 1754 identified themselves as people who use the Internet regularly while the
other 483 indicated that they do not use the Internet regularly. In addition to Internet use, participants were asked if they agree
with the statement "most people can be trusted." The results show that 807 of the Internet users agree with this statement, while
130 of the non-users agree.
Find a 90% confidence interval for the difference in the two proportions, p, -
who agree with the statement and py is the proportion for the non-internet users who agree with the statement.
PN where p, is the proportion for the internet users
Round your answers to three decimal places.
The 90% confidence interval is
to
0.237
Transcribed Image Text:In a randomly selected sample of 2237 US adults, 1754 identified themselves as people who use the Internet regularly while the other 483 indicated that they do not use the Internet regularly. In addition to Internet use, participants were asked if they agree with the statement "most people can be trusted." The results show that 807 of the Internet users agree with this statement, while 130 of the non-users agree. Find a 90% confidence interval for the difference in the two proportions, p, - who agree with the statement and py is the proportion for the non-internet users who agree with the statement. PN where p, is the proportion for the internet users Round your answers to three decimal places. The 90% confidence interval is to 0.237
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