A randomized prospective study is conducted to estimate the association between taking a drug and remission forpatients with a specific type of cancer. The estimated incidence rate ratio of remission for the treatment grouprelative to the placebo is 1.35. What is the proper interpretation of this value?An individual (from the same cancer population) who does not take the drug is 35% less likely to go intoremission as compared to an individual who has taken the drug.O In a random sample of 1,000 persons from the same cancer population, there would be 350 moreremissions if these 1,000 persons took the drug as compared to if they did not take the drug.O An individual (from the same cancer population) who takes the drug is 35% more likely to go into remissionas compared to an individual who has not taken the drug.O In a random sample of 1,000 persons from the same cancer population, there would be 650 less remissionsif these 1,000 persons took the drug as compared to if they did not take the drug.

Answered: Image /qna-images/answer/e45ec2c3-bb11-44b9-a7c7-2b5ea4951c61.jpg

Answered: A randomized prospective study is…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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PM Wed Nov 3 Stats Home Insert Draw View 8). Studies have shown that drivers who use cell phones while operating a motor passenger vehicle increase their risk of an accident. To quantify this risk, the New England Journal of Medicine (January 2, 2014) reported on the risk of a crash (or near crash) for both novice and expert drivers when using a cell phone. In a sample of 371 cases of novices using a cell phone while driving, 24 resulted in a crash (or near crash). In a sample of 1,467 cases of experts using a cell phone while driving. 67 resulted in a crash (or near crash). a). Find a 93% confidence interval for p, the true crash risk (probability) for novice drivers, also indicating the ME value. Answer: ME = b). Find a 93% confidence interval for p, the true crash risk (probability) for expert drivers, also indicating the ME value. Answer: гр, ME =
A researcher wanted to examine whether type of dog food (freeze dried meat vs generic brand kibble) would affect dogs’ attention span. The researcher hypothesized that dogs who ate freeze dried meat would have longer attention spans than those who ate generic brand kibble. The researcher used a single sample of 13 subjects, that took part in both treatment conditions. The researcher set the alpha level at .01. The mean of the difference scores (MD)was 7.0 and the SSD for the difference in attention spans was 144. What is the calculated test statistic to the nearest thousandth? Be sure to put the positive or negative sign in front of it. Note: SHOW ALL WORK!!! Based on your work above, do you reject or retain the null? reject retain Based on your conclusion regarding the null, was there a treatment effect? Yes No
From the same cohort, all cases and 10 controls per case were chosen for analysis. The following results were observed. Serum Level of Vitamin D Incident Cases of MS Healthy Individuals Above 40 ng per ml 40 20-40 ng per ml 4 40 Below 20 ng per ml 4 20 What is the odds ratio for individuals with serum levels of vitamin D of 20-40 ng per ml? O 4.0 О 30 O 1.0 O 2.0 2.
Data from the Department of Motor Vehicles indicate that 80% of all licensed drivers are older than age 25. In a sample of n = 50 people who recently received speeding tickets, 33 were older than age 25 and the other 17 were age 25 or younger. Is the age distribution for this sample significantly different from the distribution for the population of licensed drivers? Use alpha = .05. In a sample of n = 50 people who recently received parking tickets, 36 were older than age 25 and the other 14 were age 25 or younger. Is the age distribution for this sample significantly different from the distribution for the population of licensed drivers? Use alpha = .05.
According to a survey conducted by the Association for Dressing and Sauces, 85% of American adults eat salad at least once a week. A nutritionist suspect that the percentage is higher that this. She conducts a survey of 200 American adults an finds that 171 of them eat salad at least once a week. Conduct the appropriate test that addresses the nutritionist's suspicions. Use the a = 0.1 level of significance. What is the test statistic? t-score population parameter Z-Score standard deviation
A new drug to treat psoriasis has been developed and is in clinical testing. Assume that those individuals given the drug are examined before receiving the treatment and then again after receiving the treatment to determine if there was a change in their symptom status. If the initial results showed that 2.0% of individuals entered the study in remission, 77.0% of individuals entered the study with mild symptoms, 16.0% of individuals entered the study with moderate symptoms, and 5.0% entered the study with severe symptoms calculate and interpret a chi-squared test to determine if the drug was effective treating psoriasis given the information below from the final examination. A. We reject H0 because 6628.08 is greater than 11.07. We have statistically significant evidence at the alpha equals .05 level to show that the distribution of the severity of psoriasis cases at the end of the clinical trial for the sample is different from the distribution of the severity of psoriasis…
The Odds Ratio (95% CI) for hospitalization from a certain infection based upon presence versus absence of a certain risk factor was observed to be 0.6 (0.2 to 1.4). These results suggest: Statistically significant protection against hospitalization given the presence of the risk factor. Possible (though not statistically significant) protection against hospitalization given the presence of the risk factor. Possible (though not statistically significant) risk of hospitalization given the presence of the risk factor. Statistically significant risk of hospitalization given the presence of the risk factor.
The SSRUR = 161.9, SSRR = 260.6, number of restrictions = 2, n = 89, and there are 8 right hand side variables. Calculate the F statistic.

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