O 12QUESTION 12A random variable X has P( 1.2 < X < 18.8 ) 2 15/16. Use Chebyshev's Theorem to find the standard deviation of X.1.13.34.4O 2.2lick Save and Submit to save and submit. Click Save All Answers to save all answers.ASUS ViO O O

Name: O 12QUESTION 12A random variable X has P( 1.2 < X < 18.8 ) 2 15/16. U
Uploaded: 2024-03-20T07:06:27.000Z
Channel: Bartleby
Description: O 12QUESTION 12A random variable X has P( 1.2 < X < 18.8 ) 2 15/16. Use Chebyshev's Theorem to find the standard deviation of X.1.13.34.4O 2.2lick Save and Submit to save and submit. Click Save All Answers to save all answers.ASUS ViO O O

According to chebyshev's theorem, the proportion of a distribution which will lie within k standard…

Answered: A random variable X has P( 1.2 < X<…

Math

Probability

A random variable X has P( 1.2 < X< 18.8 ) 2 15/16. Use Chebyshev's Theorem to find the standard deviation of X. 1.1 3.3 4.4 2.2

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading between -2.421°C and -2.271°C.P(−2.421<Z<−2.271)
A normal random variable X has a mean of 15 and a standard deviation of 4. a. Find the value x for which P(X ≤ x) = 0.5. b. Find the value of x for which P(X > x) = 0.3
Let X and Y be independent random variables such that Var[X] = 4.8 and Var[Y ] = 9.7. How can we prove that 2X and 3Y are independent? What is the standard deviation of 2X + 3Y?
X is a normally distributed random variable with a mean of 5 and a standard deviation of 2. For which value of a is P(X > a) = 0.6293? What is a?
Assume that we have estimated the standard deviation of a sample x₁,. ., xn ER using the sample standard deviation s = ô(x₁,x2,...,xn). What does ô(−2x1, −2x2,..., -2xn) equal? A: s B: -4s C: 4s D: -2s E: 2s
Assume that adults have IQ scores that are normally distributed with a mean of μ=105 and a standard deviation σ=15. Find the probability that a randomly selected adult has an IQ less than 123.
Assume that the random variable X is normally distributed with mean = 1000 and standard deviation = 188. Let n = 18. Find P( < 947.4).
A random sample of size n1 =15 is selected from a normal population with a mean of 76 and standard deviation of 9. A second random sample size n2 =10 is taken from another normal population with mean 71 and a standard deviation 13. Let x barı and x bar2 be the sample means. Find: a. The probability that xbar1 – xbar2 exceeds 4.5 b. The probability that 3.5 s xbar1– xbar2 s 5.5
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of O°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading between 0.346°C and 1.84°C. P(0.346 < Z < 1.84)
A population has a mean of 300 and a standard deviation of 40. Suppose a simple random sample of size 100 is selected and x¯ is used to estimate μ .What is the probability that the sample mean will be within +/- 5 of the population mean?
Assume the random variable X is normally distributed with a mean of 130 and standard deviation of 21.5. State answers to THREE decimals. P (140 < x < 165) = P( x > 105) =
7.54 A random variable is Poisson distributed with A = 0.50 arrivals per minute. For the corresponding exponential distribution, and x = minutes until the next arrival, identify the mean of x and determine the following: a. P(x S 0.5) b. P(x S1.5) с. Р\х 2.5) d. P(x 3.0)