A random sample of n1 = 16 communities in western Kansas gave the following information for people under 25 years of age. x1: Rate of hay fever per 1000 population for people under 25 100 92 122 130 90 123 112 93 125 95 125 117 97 122 127 88 A random sample of n2 = 14 regions in western Kansas gave the following information for people over 50 years old. x2: Rate of hay fever per 1000 population for people over 50 94 109 103 95 110 88 110 79 115 100 89 114 85 96 (i) Use a calculator to calculate x1, s1, x2, and s2. (Round your answers to four decimal places.) x1 = s1 = x2 = s2 = (ii) Assume that the hay fever rate in each age group has an approximately normal distribution. Do the data indicate that the age group over 50 has a lower rate of hay fever? Use ? = 0.05. (a) What is the level of significance?=___ State the null and alternate hypotheses. A-H0: ?1 = ?2; H1: ?1 ≠ ?2 B-H0: ?1 > ?2; H1: ?1 = ?2 C-H0: ?1 = ?2; H1: ?1 > ?2 D-H0: ?1 = ?2; H1: ?1 < ?2 (c) Find (or estimate) the P-value. A-P-value > 0.250 B-0.125 < P-value < 0.250 C- 0.050 < P-value < 0.125 D-0.025 < P-value < 0.050 E-0.005 < P-value < 0.025 E-P-value < 0.005 (d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level ?? A-At the ? = 0.05 level, we fail to reject the null hypothesis and conclude the data are not statistically significant. B-At the ? = 0.05 level, we reject the null hypothesis and conclude the data are not statistically significant. C-At the ? = 0.05 level, we fail to reject the null hypothesis and conclude the data are statistically significant. D-At the ? = 0.05 level, we reject the null hypothesis and conclude the data are statistically significant. (e) Interpret your conclusion in the context of the application. A-Fail to reject the null hypothesis, there is insufficient evidence that the mean rate of hay fever is lower for the age group over 50. B-Reject the null hypothesis, there is insufficient evidence that the mean rate of hay fever is lower for the age group over 50. C-Reject the null hypothesis, there is sufficient evidence that the mean rate of hay fever is lower for the age group over 50. D-Fail to reject the null hypothesis, there is sufficient evidence that the mean rate of hay fever is lower for the age group over 50.

A random sample of n1 = 16 communities in western Kansas gave the following information for people under 25 years of age. x1: Rate of hay fever per 1000 population for people under 25 100 92 122 130 90 123 112 93 125 95 125 117 97 122 127 88 A random sample of n2 = 14 regions in western Kansas gave the following information for people over 50 years old. x2: Rate of hay fever per 1000 population for people over 50 94 109 103 95 110 88 110 79 115 100 89 114 85 96 (i) Use a calculator to calculate x1, s1, x2, and s2. (Round your answers to four decimal places.) x1 = s1 = x2 = s2 = (ii) Assume that the hay fever rate in each age group has an approximately normal distribution. Do the data indicate that the age group over 50 has a lower rate of hay fever? Use ? = 0.05. (a) What is the level of significance?=___ State the null and alternate hypotheses. A-H0: ?1 = ?2; H1: ?1 ≠ ?2 B-H0: ?1 > ?2; H1: ?1 = ?2 C-H0: ?1 = ?2; H1: ?1 > ?2 D-H0: ?1 = ?2; H1: ?1 < ?2 (c) Find (or estimate) the P-value. A-P-value > 0.250 B-0.125 < P-value < 0.250 C- 0.050 < P-value < 0.125 D-0.025 < P-value < 0.050 E-0.005 < P-value < 0.025 E-P-value < 0.005 (d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level ?? A-At the ? = 0.05 level, we fail to reject the null hypothesis and conclude the data are not statistically significant. B-At the ? = 0.05 level, we reject the null hypothesis and conclude the data are not statistically significant. C-At the ? = 0.05 level, we fail to reject the null hypothesis and conclude the data are statistically significant. D-At the ? = 0.05 level, we reject the null hypothesis and conclude the data are statistically significant. (e) Interpret your conclusion in the context of the application. A-Fail to reject the null hypothesis, there is insufficient evidence that the mean rate of hay fever is lower for the age group over 50. B-Reject the null hypothesis, there is insufficient evidence that the mean rate of hay fever is lower for the age group over 50. C-Reject the null hypothesis, there is sufficient evidence that the mean rate of hay fever is lower for the age group over 50. D-Fail to reject the null hypothesis, there is sufficient evidence that the mean rate of hay fever is lower for the age group over 50.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

A random sample of n₁ = 16 communities in western Kansas gave the following information for people under 25 years of age.

x₁: Rate of hay fever per 1000 population for people under 25

100	92	122	130	90	123	112	93
125	95	125	117	97	122	127	88

A random sample of n₂ = 14 regions in western Kansas gave the following information for people over 50 years old.

x₂: Rate of hay fever per 1000 population for people over 50

94	109	103	95	110	88	110
79	115	100	89	114	85	96

(i) Use a calculator to calculate x₁, s₁, x₂, and s₂. (Round your answers to four decimal places.)

x₁	=
s₁	=
x₂	=
s₂	=

(ii) Assume that the hay fever rate in each age group has an approximately normal distribution. Do the data indicate that the age group over 50 has a lower rate of hay fever? Use ? = 0.05.
(a) What is the level of significance?=___

State the null and alternate hypotheses.

A-H₀: ?₁ = ?₂; H₁: ?₁ ≠ ?₂

B-H₀: ?₁ > ?₂; H₁: ?₁ = ?₂

C-H₀: ?₁ = ?₂; H₁: ?₁ > ?₂

D-H₀: ?₁ = ?₂; H₁: ?₁ < ?₂

_{(c) Find (or estimate) the P-value.}

A-P-value > 0.250

B-0.125 < P-value < 0.250

C- 0.050 < P-value < 0.125

D-0.025 < P-value < 0.050

E-0.005 < P-value < 0.025

E-P-value < 0.005

(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level ??

A-At the ? = 0.05 level, we fail to reject the null hypothesis and conclude the data are not statistically significant.

B-At the ? = 0.05 level, we reject the null hypothesis and conclude the data are not statistically significant.

C-At the ? = 0.05 level, we fail to reject the null hypothesis and conclude the data are statistically significant.

D-At the ? = 0.05 level, we reject the null hypothesis and conclude the data are statistically significant.

(e) Interpret your conclusion in the context of the application.

A-Fail to reject the null hypothesis, there is insufficient evidence that the mean rate of hay fever is lower for the age group over 50.

B-Reject the null hypothesis, there is insufficient evidence that the mean rate of hay fever is lower for the age group over 50.

C-Reject the null hypothesis, there is sufficient evidence that the mean rate of hay fever is lower for the age group over 50.

D-Fail to reject the null hypothesis, there is sufficient evidence that the mean rate of hay fever is lower for the age group over 50.

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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