A random sample of size n= 100 yieldedp = 0.50. a. Is the sample size large enough to use the large sample approximation to construct a confidence interval for p? Explain. b. Construct a 99% confidence interval for p. c. Interpret the 99% confidence interval. d. Explain what is meant by the phrase "99% confidence interval." a. Is the sample large enough? O A. No, because nôz 15 and ng < 15. O B. Yes, because np2 15 and ng z 15. O C. No, because nô < 15 and ng « 15. O D. No, because nô < 15 and ng « 15. b. The 99% confidence interval for p is (O). (Round to two decimal places as needed.) c. Interpret this confidence interval. O A. We are confident that 99% of the population is described by the interval for p. O B. There is a 99% chance that the value of p is outside the interval. OC. We are 99% confident that p lies in the confidence interval. O D. We are confident that 99% of the population is outside the interval for p. d. Explain what is meant by the phrase "99% confidence interval." O A. The confidence interval is within 19% of the true parameter value. O B. 99% of similarly constructed intervals would be centered on the true value of the parameter. OC. There is a 99% chance that the true value of the parameter is the midpoint of the interval. O D. 99% of similarly constructed intervals would contain the true value of the parameter.
A random sample of size n= 100 yieldedp = 0.50. a. Is the sample size large enough to use the large sample approximation to construct a confidence interval for p? Explain. b. Construct a 99% confidence interval for p. c. Interpret the 99% confidence interval. d. Explain what is meant by the phrase "99% confidence interval." a. Is the sample large enough? O A. No, because nôz 15 and ng < 15. O B. Yes, because np2 15 and ng z 15. O C. No, because nô < 15 and ng « 15. O D. No, because nô < 15 and ng « 15. b. The 99% confidence interval for p is (O). (Round to two decimal places as needed.) c. Interpret this confidence interval. O A. We are confident that 99% of the population is described by the interval for p. O B. There is a 99% chance that the value of p is outside the interval. OC. We are 99% confident that p lies in the confidence interval. O D. We are confident that 99% of the population is outside the interval for p. d. Explain what is meant by the phrase "99% confidence interval." O A. The confidence interval is within 19% of the true parameter value. O B. 99% of similarly constructed intervals would be centered on the true value of the parameter. OC. There is a 99% chance that the true value of the parameter is the midpoint of the interval. O D. 99% of similarly constructed intervals would contain the true value of the parameter.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A random sample of size n= 100 yielded p= 0.50.
a. Is the sample size large enough to use the large sample approximation to construct a confidence interval for p? Explain.
b. Construct a 99% confidence interval for p
c. Interpret the 99% confidence interval.
d. Explain what
meant by the phrase "99% confidence interval."
a. Is the sample large enough?
O A. No, because np z 15 and ng < 15.
O B. Yes, because np 2 15 and ng z 15
O C. No, because np < 15 and ng < 15
O D. No, because np< 15 and ng < 15.
b. The 99% confidence interval for p is ( )
(Round to two decimal places as needed.)
c. Interpret this confidence interval.
O A. We are confident that 99% of the population is described by the interval for p
O B. There is a 99% chance that the value of p is outside the interval.
O C. We are 99% confident that p lies in the confidence interval.
O D. We are confident that 99% of the population is outside the interval for p.
d. Explain what
meant by the phrase "99% confidence interval."
O A. The confidence interval is within 1% of the true parameter value.
O B. 99% of similarly constructed intervals would be centered on the true value of the parameter.
O C. There is a 99% chance that the true value of the parameter is the midpoint of the interval.
O D. 99% of similarly constructed intervals would contain the true value of the parameter.
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