Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a margin of error of 5 percentage points and use a confidence level of 90%. Complete parts (a)and (b) below.a. Assume that p and q are unknown.n = 271(Round up to the nearest integer.)b. Assume that 24% of adults can wiggle their ears.n =-Q(Round up to the nearest integer.)

Step 1: Given informationConfidence level, c = 0.90Margin of error, E = 0.05 Step 2: Part (a)The…

Answered: Find the sample size needed to estimate…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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HOTSPOT LABEL The times (in seconds) of 8 runners for the 100-yard dash are recorded and used to determine the following calculations. Mean: 11.8 Median: 12.2 CO Mode: 12.5 Range: 3.2 The timekeeper had difficulties with the stopwatch and did not start the time until the runners had been running for 1.5 seconds. What would these calcula- tions be if this 1.5 seconds were added to each runner's 100-yard dash time? . Press each hotspot. Label the corresponding number below with the requested value. ▶ C «» Press to hear a reminder or hint for this problem. IQR: 2.4 100 All Charge
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A survey was conducted that asked 976 people how many books they had read in the past year. Results indicated that x= 14.2 books and s= 17.7 books. Construct a 90% confidence interval for the mean number of books people read Interpret the Construct a 90% confidence interval for the mean number of books people read and interpret the result. Select the correct choice below and fill in the answer boxes to complete your choice. (Use ascending order. Round to two decimal places as needed.) O A. There is 90% confidence that the population mean number of books read is between and O B. If repeated samples are taken, 90% of them will have a sample mean between and OC. There is a 90% probability that the true mean number of books read is between and O Time Remaining: 00:58:23 Next Statcrunch 350 PM O 67°F Sunny ヘ回 12/1/2021 P Type here to search DELL F9 F10 F11 F12 PrtScr Insert Delete F3 F4 F5 F6 F7 F8 Esc F1 F2 @ # $ % & Backspace 2 3 4 6 7 1 W E R Y U Tab Enter A S D J K Caps Lock
Use the expression in the accompanying discussion of sample size to find the size of each sample if you want to estimate the difference between proportions of men and women who own smartphones assume that you want 99% confidence that your area is no more than 0.045
Use the expression in the accompanying discussion of sample size to find the size of each sample if you want to estimate the difference between proportions of men and women who own smartphones. Assume that you want 90% confidence that your error is no more than 0.04. The sample should include ___ men and ___ women.
Bill Alther is a zoologist who studies Anna's hummingbird (Calypte anna). (Reference: Hummingbirds, K. Long, W. Alther.) Suppose that in a remote part of the Grand Canyon, a random sample of six of these birds was caught, weighed, and released. The weights (in grams) were as follows. 3.7 2.9 3.8 4.2 4.8 3.1 The sample mean is = 3.75 grams. Let x be a random variable representing weights of hummingbirds in this part of the Grand Canyon. We assume that x has a normal distribution and ? = 0.64 gram. Suppose it is known that for the population of all Anna's hummingbirds, the mean weight is ? = 4.30 grams. Do the data indicate that the mean weight of these birds in this part of the Grand Canyon is less than 4.30 grams? Use ? = 0.10. Level of significance = .10 Null and alternate hypotheses. - H0: ? = 4.3 g; H1: ? < 4.3 g; left-tailed Sampling Distribution - The standard normal, since we assume that x has a normal distribution with known ? Compute the z value of the sample test…
Bill Alther is a zoologist who studies Anna's hummingbird (Calypte anna). (Reference: Hummingbirds, K. Long, W. Alther.) Suppose that in a remote part of the Grand Canyon, a random sample of six of these birds was caught, weighed, and released. The weights (in grams) were as follows. 3.7 2.9 3.8 4.2 4.8 3.1 The sample mean is = 3.75 grams. Let x be a random variable representing weights of hummingbirds in this part of the Grand Canyon. We assume that x has a normal distribution and σ = 0.64 gram. Suppose it is known that for the population of all Anna's hummingbirds, the mean weight is μ = 4.30 grams. Do the data indicate that the mean weight of these birds in this part of the Grand Canyon is less than 4.30 grams? Use ? = 0.10. (a) What is the level of significance? (Enter a number.) State the null and alternate hypotheses. Will you use a left-tailed, right-tailed, or two-tailed test? H0: μ = 4.3 g; H1: μ > 4.3 g; right-tailed H0: μ < 4.3 g; H1: μ = 4.3 g; left-tailed…
A survey was conducted that asked 1013 people how many books they had read in the past year. Results indicated that x=10.3 books and s=16.6books. Construct a 90% confidence interval for the mean number of books people read. Interpret the interval. Construct a 90% confidence interval for the mean number of books people read and interpret the result. Select the correct choice below and fill in the answer boxes to complete your choice. (Use ascending order. Round to two decimal places as needed.) A. There is a 90% probability that the true mean number of books read is between ___ and ____ B. There is 90% confidence that the population mean number of books read is between ___ and ____. C. If repeated samples are taken, 90% of them will have a sample mean between ___ and ___.
Answer only d and f please I have already answer of a, b and c don't solve
Use the confidence interval to find the estimated margin of error. Then find the sample mean. A biologist reports a confidence interval of (2.1,2.5) when estimating the mean height (in centimeters) of a sample of seedlings.
Use the confidence interval to find the margin of error and the sample mean. (1.57,1.95) The margin of error is enter your response here.
A survey was conducted that asked 963 people how many books they had read in the past year. Results indicated that x=14.7 books and s=17.8 books. Construct a 90% confidence interval for the mean number of books people read. Interpret the interval.Construct a 90% confidence interval for the mean number of books people read and interpret the result. Select the correct choice below and fill in the answer boxes to complete your choice.(Use ascending order. Round to two decimal places as needed.)A. If repeated samples are taken, 90% of them will have a sample mean between ___ and ____ B. There is a 90% probability that the true mean number of books read is between ____ and ___ C. There is a 90% confidence that the population mean number of books read is between ___ and ___

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