A random sample of seven students was taken and the number of times the student visited office hours is summarized: - Logan 2, Chengcen - 9, Scott - 5, Ami - 6, Madison - 2, Rebecca - 5, Xin - 2 Compute the value of (mode + median + mean + third quartile). 1. 16.56 2. 18.30 3. 19.17 4. 17.43 5. 15.69
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- A Michigan study concerning preference for outdoor activities used a questionnaire with a six-point Likert-type response in which 1 designated "not important" and 6 designated "extremely important." A random sample of n1 = 45 adults were asked about fishing as an outdoor activity. The mean response was x1 = 4.9. Another random sample of n2 = 55 adults were asked about camping as an outdoor activity. For this group, the mean response was x2 = 4.0. From previous studies, it is known that σ1 = 1.5 and σ2 = 2.0. Does this indicate a difference (either way) regarding preference for camping versus preference for fishing as an outdoor activity? Use a 5% level of significance. Note: A Likert scale usually has to do with approval of or agreement with a statement in a questionnaire. For example, respondents are asked to indicate whether they "strongly agree," "agree," "disagree," or "strongly disagree" with the statement. (a) What is the level of significance? What is the value of the sample…A Michigan study concerning preference for outdoor activities used a questionnaire with a six-point Likert-type response in which 1 designated "not important" and 6 designated "extremely important." A random sample of n1 = 44 adults were asked about fishing as an outdoor activity. The mean response was x1 = 4.9. Another random sample of n2 = 47 adults were asked about camping as an outdoor activity. For this group, the mean response was x2 = 5.6. From previous studies, it is known that σ1 = 1.2 and σ2 = 2.0. Does this indicate a difference (either way) regarding preference for camping versus preference for fishing as an outdoor activity? Use a 5% level of significance. 1. What is the value of the sample test statistic? (Test the difference μ1 − μ2. Round your answer to two decimal places.) 2. Find (or estimate) the P-value. (Round your answer to four decimal places.)Listed below are student evaluation of female professions and male professors. Use a 0.05 significance level to test the claim that female professors and male professors have the same mean evaluations ratings. P-value: 0.758
- A Michigan study concerning preference for outdoor activities used a questionnaire with a six-point Likert-type response in which 1 designated "not important" and 6 designated "extremely important." A random sample of n1 = 44 adults were asked about fishing as an outdoor activity. The mean response was x1 = 4.9. Another random sample of n2 = 49 adults were asked about camping as an outdoor activity. For this group, the mean response was x2 = 4.1. From previous studies, it is known that ?1 = 1.5 and ?2 = 2.0. Does this indicate a difference (either way) regarding preference for camping versus preference for fishing as an outdoor activity? Use a 5% level of significance. Note: A Likert scale usually has to do with approval of or agreement with a statement in a questionnaire. For example, respondents are asked to indicate whether they "strongly agree," "agree," "disagree," or "strongly disagree" with the statement.A pollof 2000 randomly selected students in grades 6 through 8 was conducted and found that 48% enjoy playing sports. Is the 48% result a statistic or a parameter?6) A researcher is interested in whether women like Justin Bieber's music more than men. The extent to which people liked Bieber's music was measured on a 10 point scale ranging from 1 = do not like at all, to 10 like Justin Bieber's music more than men (alpha = .05). very much like. Using the data below, please determine whether women Women Men 7 4 8 7 4 a) What type statistical analysis should you perform? Please explain your rationale b) Please state the null and alternative hypotheses c) Please write out the results (t-value, df, p-value) and make a decision d) Please make a general conclusion (no stats talk)
- A study from 2014 found that adults in the US spend an average of 11 hours per day watching, reading, listening to or simply interacting with media. Researchers at UCLA suspect students spend less time engaging media. They grouped UCLA students by class section, randomly selected 20 class sections, and administered a survey to each student in those randomly selected class sections. The following data represents the mean time (in hours) per day spent engaging media for each of the randomly selected classes: 9.5 11.5 6.0 7.5 8 9.5 10.5 11 12 8.2 5 9.5 8.2 9.3 10.8 11 13 8.6 9.5 10.5 What would be the 99% Confidence Interval for mean time (in hours) spent per day engaging media for UCLA students. Do this "by hand", using appripriate symbols/formulas/tables.use ms excel, thank you!A study from 2014 found that adults in the US spend an average of 11 hours per day watching, reading, listening to or simply interacting with media. Researchers at UCLA suspect students spend less time engaging media. They grouped UCLA students by class section, randomly selected 20 class sections, and administered a survey to each student in those randomly selected class sections. The following data represents the mean time (in hours) per day spent engaging media for each of the randomly selected classes: 9.5 11.5 6.0 7.5 8 9.5 10.5 11 12 8.2 5 9.5 8.2 9.3 10.8 11 13 8.6 9.5 10.5 What would be the calculator steps to find standard deviaton, rounded to 3 decimal places?
- A Michigan study concerning preference for outdoor activities used a questionnaire with a six-point Likert-type response in which 1 designated "not important" and 6 designated "extremely important." A random sample of n1 = 41 adults were asked about fishing as an outdoor activity. The mean response was x1 = 4.9. Another random sample of n2 = 50 adults were asked about camping as an outdoor activity. For this group, the mean response was x2 = 5.7. From previous studies, it is known that ?1 = 1.6 and ?2 = 1.5. Does this indicate a difference (either way) regarding preference for camping versus preference for fishing as an outdoor activity? Use a 5% level of significance.Note: A Likert scale usually has to do with approval of or agreement with a statement in a questionnaire. For example, respondents are asked to indicate whether they "strongly agree," "agree," "disagree," or "strongly disagree" with the statement. (a) What is the level of significance? .05 State the null and alternate…The dataset "nurses" is a random sample of 1,000 cases from “Health Care Provider Credential Data” from Washington State Open Data Portal. In the sample, there are 418 CNA's and 278 of the CNA's have expired credentials. Use the statistics from the nurses dataset to answer the following question: "With 90% confidence, what percent of all CNA's on Washington State's healthcare provider list are expired?"
