A random sample of residents from various income brackets were asked their opinion on tax reform for the country of Guyana. The data so gathered were analyzed by a statistician and the results he obtained using MINITAB are shown below: Expected counts are printed below observed counts Low Middle High 14 Total For 26 75 115 (30.67) (51.11) (33.22) Against 60 95 105 260 (69.33) (115.56) (**) 30 (33.33) 200 Neutral 34 11 75 (20) (21.67) Total 130 450 Chi-sq - 0.71 + 11.17 + 11.12 + 3.66 + 11.89 + 9.8 + 0.33 + 5.25 - 55.2 DF - ??, p-value -??? a) Carefully define the null and alternative hypotheses of the xz test underlying the generation of the above table. b) Find the missing values *, **', ****, '??' and ???'. c) What is the conclusion of this test? Give reasons for your answer.

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Using the chi-square test table to answer this question. Proper working out and right answers required.

 

 

A random sample of residents from various income brackets were asked their opinion on tax reform
for the country of Guyana. The data so gathered were analyzed by a statistician and the results he
obtained using MINITAB are shown below:
Expected counts are printed below observed counts
Total
115
Low
Middle
нigh
For
26
75
14
(30.67)
(51.11)
(33.22)
Against
60
95
105
260
(69.33)
(115.56)
(**)
Neutral
34
30
11
75
(20)
(33.33)
(21.67)
Total
200
130
450
Chi-sq =
0.71 +
11.17 +
11.12 +
3.66 +
11.89 +
9.8 +
0.33 +
5.25 =
55.2
DF = ??, p-value =???
a) Carefully define the null and alternative hypotheses of the x2 test underlying the generation
of the above table.
b) Find the missing values *', ***', ****', '??' and ???'.
c) What is the conclusion of this test? Give reasons for your answer.
Transcribed Image Text:A random sample of residents from various income brackets were asked their opinion on tax reform for the country of Guyana. The data so gathered were analyzed by a statistician and the results he obtained using MINITAB are shown below: Expected counts are printed below observed counts Total 115 Low Middle нigh For 26 75 14 (30.67) (51.11) (33.22) Against 60 95 105 260 (69.33) (115.56) (**) Neutral 34 30 11 75 (20) (33.33) (21.67) Total 200 130 450 Chi-sq = 0.71 + 11.17 + 11.12 + 3.66 + 11.89 + 9.8 + 0.33 + 5.25 = 55.2 DF = ??, p-value =??? a) Carefully define the null and alternative hypotheses of the x2 test underlying the generation of the above table. b) Find the missing values *', ***', ****', '??' and ???'. c) What is the conclusion of this test? Give reasons for your answer.
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