A random sample of 97 cans of coke were observed and yeilded a mean of 353.3 mL and a standard deviation of 1.75 mL. Coke says that the population mean of their cans is 355 mL. Do we have enough evidence to show that the mean is not 355 mL? Use a = 0.05 and use our tables.

A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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A random sample of 97 cans of coke were observed and yeilded a mean of
353.3 mL and a standard deviation of 1.75 mL. Coke says that the population mean
of their cans is 355 mL. Do we have enough evidence to show that the mean is not
355 mL? Use a = 0.05 and use our tables.
Select the correct null and alternative hypotheses:
OA. Ho X = 353.3,H₁ : X ‡ 353.3
Ο Β. Η : μ = 355,HA : μ < 355
OC. Ho μ = 355,H₁ : μ355
OD. Ho μ = 355,H₁ μ> 355
OE. Ho: X = 353.3,HA: X < 353.3
OF. Ho X = 353.3,HA: X > 353.3
OG. None of the above
:
Select the type of distribution to be used in this question:
OA. Z-distribution
OB. t-distribution
OC. Chi-Square distribution
OD. None of the above
The rejection region for this test is:
OA. (-∞, -2.575)
OB. (-∞, -1.96)
OC. (1.96, ∞)
OD. (1.645, ∞)
OE. (-∞, -1.96) U (1.96,∞)
OF. (2.575, ∞)
OG. (-∞, -2.575) U (2.575, ∞o)
OH. (-∞, -1.645)
OI. (-∞, -1.645) U (1.645, ∞)
OJ. None of the above
Test statistic =
The conclusion for this test is:
OA. Reject Ho
OB. Fail to Reject HA
OC. Reject HA
OD. Fail to Reject Ho
OE. None of the above
Transcribed Image Text:A random sample of 97 cans of coke were observed and yeilded a mean of 353.3 mL and a standard deviation of 1.75 mL. Coke says that the population mean of their cans is 355 mL. Do we have enough evidence to show that the mean is not 355 mL? Use a = 0.05 and use our tables. Select the correct null and alternative hypotheses: OA. Ho X = 353.3,H₁ : X ‡ 353.3 Ο Β. Η : μ = 355,HA : μ < 355 OC. Ho μ = 355,H₁ : μ355 OD. Ho μ = 355,H₁ μ> 355 OE. Ho: X = 353.3,HA: X < 353.3 OF. Ho X = 353.3,HA: X > 353.3 OG. None of the above : Select the type of distribution to be used in this question: OA. Z-distribution OB. t-distribution OC. Chi-Square distribution OD. None of the above The rejection region for this test is: OA. (-∞, -2.575) OB. (-∞, -1.96) OC. (1.96, ∞) OD. (1.645, ∞) OE. (-∞, -1.96) U (1.96,∞) OF. (2.575, ∞) OG. (-∞, -2.575) U (2.575, ∞o) OH. (-∞, -1.645) OI. (-∞, -1.645) U (1.645, ∞) OJ. None of the above Test statistic = The conclusion for this test is: OA. Reject Ho OB. Fail to Reject HA OC. Reject HA OD. Fail to Reject Ho OE. None of the above
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