A random sample of 90 observations produced a mean of x = 34.6 from a population with a normal distribution and a standard deviation o = 4.77. (a) Find a 95% confidence interval for µ <μ< (b) Find a 99% confidence interval for u <μ< (c) Find a 90% confidence interval for μ <μ <
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A: Answer: Given, n=85 μ=275 x=284 σ=30 (a) Option E. H0:μ=275 VS HA:μ>275(claim)
Q: A random sample of 85 eighth grade students' scores on a national mathematics assessment test has a…
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A: Hey there! Thank you for posting the question. Since your question has more than 3 parts, we are…
Q: A company that makes cola drinks states that the mean caffeine content per 12-ounce bottle of cola…
A: Given Information : A company that makes cola drinks states that the mean caffeine content per…
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A: Solution: From the given information, n=4, µ=80, σ=10 and M=90.
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- In a survey of adults with diabetes, the average body mass index (BMI) in a sample of 1924 women was 31.10 with a standard deviation of 0.4. The BMI in a sample of 1555 men was 30.30, with a standard deviation of 0.7. (a) Construct a 95% confidence interval for the difference in the mean BMI between women and men with diabetes. Let μ1 denote the mean BMI for women with diabetes. Use the TI-84 calculator and round the answers to two decimal places. (b)The confidence interval ( contradicts/does not contradict) this claimA random sample of 130130 observations produced a mean of ?=30.2x¯=30.2 from a population with a normal distribution and a standard deviation ?=4.49σ=4.49. (a) Find a 9999% confidence interval for ?μAn article reports that the average initial rate of absorption (in g/min·cm2) for a sample of five clay bricks with fine glass particles added was 1299.8 with a standard deviation of 329.8, and the average for another sample of five bricks without glass particles added was 4500.8 with a standard deviation of 271.6. Let μXμX represent the population mean without glass particles and let μYμY represent the population mean with glass particles. Find a 98% confidence interval for the difference μX−μYμX−μY. Round down the degrees of freedom to the nearest integer and round the answers to three decimal places.
- A pilot study of a new antihypertensive agent is performed for the purpose of planning a larger study. Five patients who have a mean DBP of at least 95 mm Hg are recruited for the study and are kept on the agent for 1 month. After 1 month the observed mean decline in DBP in these five patients is 4.4 mm Hg with a standard deviation of 8 mm Hg. (a) If ?d = true mean difference in DBP between baseline and 1 month, then how many patients would be needed to have a 90% chance of detecting a significant change in DBP over 1 month using a one-tailed test with a significance level of 5%? Assume that the true mean and standard deviation of the DBP difference were the same as observed in the pilot study. ______ # patients (b) Suppose we conduct a study of the preceding hypothesis based on 24 participants. What is the probability we will be able to reject H0 using a one-sided test at the 5% level if the true mean and standard deviation of the DBP difference are the same as in…A random sample of 88 eighth grade students' scores on a national mathematics assessment test has a mean score of 283. This test result prompts a state school administrator to declare that the mean score for the state's eighth graders on this exam is more than 275. Assume that the population standard deviation is 33. At α=0.08, is there enough evidence to support the administrator's claim? Complete parts (a) through (e).Find tα/2 when n=12 for the 95% confidence interval for the mean.
- A random sample of 82 eighth grade students' scores on a national mathematics assessment test has a mean score of 280. This test result prompts a state school administrator to declare that the mean score for the state's eighth graders on this exam is more than 275. Assume that the population standard deviation is 36. At α=0.05, is there enough evidence to support the administrator's claim? Find the standardized test statistic z, and its corresponding area. z=enter your response here (Round to two decimal places as needed.) Recall that a standard normal distribution table gives the area to the left of a z-score. Determine the area to the left of z. Find the P Value Decide whether to reject or fail to reject the null hypothesis. Interpret your decision in the context of the original claim.A random sample of 28 lunch orders at Noodles & Company showed a standard deviation of $6.24. Find the 99 percent confidence interval for the population standard deviation. Use Excel to obtain χ2L=CHISQ.INV(α/2,d.f.)χL2=CHISQ.INV(α/2,d.f.) and χ2U=CHISQ.INV.RT(α/2,d.f.)χU2=CHISQ.INV.RT(α/2,d.f.) (Round your answers to 2 decimal places.) The 99% confidence interval is from _________ to____________ .An important indicator of lung function is forced expiratory volume (FEV), which is the volume of air that a person can expire in one second. Dr. Hernandez plans to measure FEV in a random sample of n individuals from a certain population, and to use the sample mean to estimate of the population mean. The population distribution of FEV is assumed to be normal with mean mu-3000 ml and SD sigma=400 ml. Which of the following statements is correct regarding the sampling distribution of the sample mean? Ⓒa. It is the theoretical distribution of a sample statistic (in this case the sample mean). b. It is the theoretical distribution of all individuals in the population. Oc It is the observed distribution of all individuals in the sample. QUESTION 2 Suppose sample size is n-64. What is the mean of the sampling distribution of y? Ⓒa.50 b.375 c400 Od 3000
- The time it takes for a compact fluorescent bulb to reach full brightness is normally distributed with mean 29.9 seconds and standard deviation 4.1 seconds. Find and interpret the z-score for x = 26.4.A random sample of 121 observations produced a sample mean of 31. Find the critical and observed values of z for the following test of hypothesis using The population standard deviation is known to be 7 and the population distribution is normal. H0: mean= 28 versus H1: mean > 28 z critical= z observed=A random sample of 10 night students was taken with a sample mean GPA of 3.5 and a standard deviation of 0.07. A random sample of 15 day students was taken with a sample mean GPA of 3.48 and a standard deviation of 0.04. Test the claim that the mean GPA of night students (N) is greater than the mean GPA of day students (μD) at a = 0.05. Assume that the data come from normal populations with unequal variances. Round your answers to three decimal places, and round any interim calculations to four decimal places. Fill in the hypotheses below (click the circle to the left of the correct answer): Ho: Tdp μN În ? ✓ μN În PμD F d Ha: μDO Ха PO μN În ? ✓ În μN Xd μD This test is Select an answer HD
