a random sample of 8 people, the mean commute time to work was 35.5 minutes and the standard deviation was 7.3 minutes. A 95% confidence interval using t-distribution was calculated to be (29.4, 41.6). After researching commute times to work, it was found that the population standard deviation is 9.3 minutes. Find the margin of error and construct a 95% confidence interval using the standard normal distribution with the appropriate calculations for standard deviation that is known. Compare the results
a random sample of 8 people, the mean commute time to work was 35.5 minutes and the standard deviation was 7.3 minutes. A 95% confidence interval using t-distribution was calculated to be (29.4, 41.6). After researching commute times to work, it was found that the population standard deviation is 9.3 minutes. Find the margin of error and construct a 95% confidence interval using the standard normal distribution with the appropriate calculations for standard deviation that is known. Compare the results
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
In a random sample of 8 people, the mean commute time to work was 35.5 minutes and the standard deviation was 7.3 minutes.
A 95% confidence interval using t-distribution was calculated to be (29.4, 41.6). After researching commute times to work, it was found that the population standard deviation is 9.3 minutes. Find the margin of error and construct a 95% confidence interval using the standard
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
Similar questions
- In a test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 5.1 and a standard deviation of 16.8. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? mg/dL <µ
