A random sample of 45 home theater systems has a mean price of $139.00. Assume the population standard deviation is $15.70.
A random sample of 45 home theater systems has a mean price of $139.00. Assume the population standard deviation is $15.70.
A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
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![You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the
population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals.
EM
Re...
A random sample of 45 home theater systems has a mean price of $139.00. Assume the population standard deviation is $15.70.
Construct a 90% confidence interval for the population mean.
The 90% confidence interval is ( ).
(Round to two decimal places as needed.)
Construct a 95% confidence interval for the population mean.
The 95% confidence interval is ( ).
(Round to two decimal places as needed.)
Interpret the results. Choose the correct answer below.
O A. With 90% confidence, it can be said that the sample mean price lies in the first interval. With 95% confidence, it can be said that the sample mean price
lies in the second interval. The 95% confidence interval is wider than the 90%.
O B. With 90% confidence, it can be said that the population mean price lies in the first interval. With 95% confidence, it can be said that the population
mean price lies in the second interval. The 95% confidence interval is wider than the 90%.
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Professional
Ref.pdf
O C. With 90% confidence, it can be said that the population mean price lies in the first interval. With 95% confidence, it can be said that the population
mean price lies in the second interval. The 95% confidence interval is narrower than the 90%.
Click to select your answer(s).
Take a Test - Micha...
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gSearch Textbook So.
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Transcribed Image Text:You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the
population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals.
EM
Re...
A random sample of 45 home theater systems has a mean price of $139.00. Assume the population standard deviation is $15.70.
Construct a 90% confidence interval for the population mean.
The 90% confidence interval is ( ).
(Round to two decimal places as needed.)
Construct a 95% confidence interval for the population mean.
The 95% confidence interval is ( ).
(Round to two decimal places as needed.)
Interpret the results. Choose the correct answer below.
O A. With 90% confidence, it can be said that the sample mean price lies in the first interval. With 95% confidence, it can be said that the sample mean price
lies in the second interval. The 95% confidence interval is wider than the 90%.
O B. With 90% confidence, it can be said that the population mean price lies in the first interval. With 95% confidence, it can be said that the population
mean price lies in the second interval. The 95% confidence interval is wider than the 90%.
PDF
Professional
Ref.pdf
O C. With 90% confidence, it can be said that the population mean price lies in the first interval. With 95% confidence, it can be said that the population
mean price lies in the second interval. The 95% confidence interval is narrower than the 90%.
Click to select your answer(s).
Take a Test - Micha...
w
gSearch Textbook So.
DELL
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1 - Writing given data
Given that
Random sample size (n) =45
Mean price ()= $139
Population standard deviation ()=$15.70
We know that
Confidence interval (CI)
For 90% confidence (Zc ) =1.645
For 95% confidence (Zc) = 1.96
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