A random sample of 4040 adults with no children under the age of 18 years results in a mean daily leisure time of 5.135.13 hours, with a standard deviation of 2.462.46 hours. A random sample of 4040 adults with children under the age of 18 results in a mean daily leisure time of 4.254.25 hours, with a standard deviation of 1.711.71 hours. Construct and interpret a 9090% confidence interval for the mean difference in leisure time between adults with no children and adults with children left parenthesis mu 1 minus mu 2 right parenthesisμ1−μ2. Let mu 1μ1 represent the mean leisure hours of adults with no children under the age of 18 and mu 2μ2 represent the mean leisure hours of adults with children under the age of 18. The 90%confidence interval for left parenthesis mu 1 minus mu 2 right parenthesisμ1−μ2 is the range from hours to hours. (Round to two decimal places as needed.)
A random sample of 4040 adults with no children under the age of 18 years results in a mean daily leisure time of 5.135.13 hours, with a standard deviation of 2.462.46 hours. A random sample of 4040 adults with children under the age of 18 results in a mean daily leisure time of 4.254.25 hours, with a standard deviation of 1.711.71 hours. Construct and interpret a 9090% confidence interval for the mean difference in leisure time between adults with no children and adults with children left parenthesis mu 1 minus mu 2 right parenthesisμ1−μ2. Let mu 1μ1 represent the mean leisure hours of adults with no children under the age of 18 and mu 2μ2 represent the mean leisure hours of adults with children under the age of 18. The 90%confidence interval for left parenthesis mu 1 minus mu 2 right parenthesisμ1−μ2 is the range from hours to hours. (Round to two decimal places as needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
A random sample of
4040
adults with no children under the age of 18 years results in a mean daily leisure time of
5.135.13
hours, with a standard deviation of
2.462.46
hours. A random sample of
4040
adults with children under the age of 18 results in a mean daily leisure time of
4.254.25
hours, with a standard deviation of
1.711.71
hours. Construct and interpret a
9090%
confidence interval for the mean difference in leisure time between adults with no children and adults with children
left parenthesis mu 1 minus mu 2 right parenthesisμ1−μ2.
Let
mu 1μ1
represent the mean leisure hours of adults with no children under the age of 18 and
mu 2μ2
represent the mean leisure hours of adults with children under the age of 18.The 90%confidence interval for
range from
hours to
hours.
left parenthesis mu 1 minus mu 2 right parenthesisμ1−μ2
is the (Round to two decimal places as needed.)
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