A random sample of 4040 adults with no children under the age of 18 years results in a mean daily leisure time of 5.995.99 hours, with a standard deviation of 2.292.29 hours. A random sample of 4040 adults with children under the age of 18 results in a mean daily leisure time of 4.414.41 hours, with a standard deviation of 1.661.66 hours. Construct and interpret a 9090% confidence interval for the mean difference in leisure time between adults with no children and adults with children left parenthesis mu 1 minus mu 2 right parenthesisμ1−μ2. Let mu 1μ1 represent the mean leisure hours of adults with no children under the age of 18 and mu 2μ2 represent the mean leisure hours of adults with children under the age of 18. The 9090% confidence interval for left parenthesis mu 1 minus mu 2 right parenthesisμ1−μ2 is the range from nothing hours to nothing hours. (Round to two decimal places as needed.)
A random sample of 4040 adults with no children under the age of 18 years results in a mean daily leisure time of 5.995.99 hours, with a standard deviation of 2.292.29 hours. A random sample of 4040 adults with children under the age of 18 results in a mean daily leisure time of 4.414.41 hours, with a standard deviation of 1.661.66 hours. Construct and interpret a 9090% confidence interval for the mean difference in leisure time between adults with no children and adults with children left parenthesis mu 1 minus mu 2 right parenthesisμ1−μ2. Let mu 1μ1 represent the mean leisure hours of adults with no children under the age of 18 and mu 2μ2 represent the mean leisure hours of adults with children under the age of 18. The 9090% confidence interval for left parenthesis mu 1 minus mu 2 right parenthesisμ1−μ2 is the range from nothing hours to nothing hours. (Round to two decimal places as needed.)
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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Question
A random sample of
4040
adults with no children under the age of 18 years results in a mean daily leisure time of
5.995.99
hours, with a standard deviation of
2.292.29
hours. A random sample of
4040
adults with children under the age of 18 results in a mean daily leisure time of
4.414.41
hours, with a standard deviation of
1.661.66
hours. Construct and interpret a
9090%
confidence interval for the mean difference in leisure time between adults with no children and adults with children
left parenthesis mu 1 minus mu 2 right parenthesisμ1−μ2.
Let
mu 1μ1
represent the mean leisure hours of adults with no children under the age of 18 and
mu 2μ2
represent the mean leisure hours of adults with children under the age of 18.The
range from
9090%
confidence interval for
left parenthesis mu 1 minus mu 2 right parenthesisμ1−μ2
is the nothing
hours to
nothing
hours.(Round to two decimal places as needed.)
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