A random sample of 400 men from one stage gives the mean payof Rs. 200 per day with a standard deviation of Rs. 10. Anotherrandom sample of 400 men has a mean pay of Rs. 190 per day witha standard deviation of Rs. 10. Construct 99% confidence intervalfor 4-₂.a. 6.28, 17.41b. 2.86, 14.71c. 8.26, 14.17d. 8.26, 11.47e. NONE OF THE ABOVE

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Answered: A random sample of 400 men from one…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A simple random sample of 60 items resulted in a sample mean of 71. The population standard deviation is 13. a. Compute the 95% confidence interval for the population mean (to 1 decimal). Assume that the same sample mean was obtained from a sample of 120 items. Provide a 95% confidence interval for the population mean (to 2 decimals).
Do the mean weights of male college freshmen and male college seniors differ? There are arguments for and against this question. The mean weight, μx of college freshmen will be compared to the mean weight, My of college seniors. The true values of Mx and My are unknown. It is recognized that the true standard deviations are x = 13 for male college freshmen and dy = 24 for male college seniors. We take a random sample of m = 431 college freshmen and a random sample of n=289 college seniors. The mean weights were x = 178 for male college freshmen and y = 185 for male college seniors. Assuming independence between the samples and assuming the weights are normally distributed we would like to estimate My - My. a) What is the standard deviation of the distribution of x?[ b) What is the standard deviation of the distribution of x-y? c) Create a 95% confidence interval for Mx - Hy? d) What is the length of the confidence interval in part c) ? e) If we let n stay at 289 but vary m, what is the…
Suppose a randomly selected sample of n = 62 men has a mean foot length of x = 28 cm, and the standard deviation of the sample is 2 cm. Calculate an approximate 95% confidence interval for the mean foot length of men. (Round the answers to one decimal place.) In the study, n = 45 men were put on a diet. The men who dieted lost an average of 5.6 kg, with a standard deviation of 3.6 kg. (a) Compute the standard error of the mean for the men who dieted. (Round the answer to two decimal places.)kg(b) Compute an approximate 95% confidence interval for the mean weight loss for the men who dieted. (Round your answer to the nearest hundredth.)An approximate 95% confidence interval is to kg
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According to a report done by S & J Power, the mean lifetime of the light bulbs it manufactures is 49 months. A researcher for a consumer advocate group ests this by selecting 70 bulbs at random. For the bulbs in the sample, the mean lifetime is 46 months. It is known that the population standard deviation of he lifetimes is 9 months. Can we conclude, at the 0.01 level of significance, that the population mean lifetime, μ, of light bulbs made by this manufacturer differs from 49 months? Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below. (If necessary, consult a list of formulas.) (a) State the null hypothesis H, and the alternative hypothesis H₁. Ho :D H₁ :0 (b) Determine the type of test statistic to use. (Choose one) ▼ (c) Find the value of the test statistic. (Round to three or more decimal places.) 0 (d) Find the p-value. (Round to three or more decimal places.)…
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Suppose a randomly selected sample of n = 69 men has a mean foot length of x = 28.3 cm, and the standard deviation of the sample is 3 cm. Calculate an approximate 95% confidence interval for the mean foot length of men. (Round the answers to one decimal place.) to cm
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