A random sample of 212 high school students in a particular town showed that 56 smoke on a regular basis. Find the 95% confidence interval estimating the population percentage for smokers at this high school. Suppose the national average for smokers in high schools is 34.2%. Does it appear that the students in this particular town smoke less than the national average? Explain why. Round confidence interval to nearest thousandth. A random sample of 212 high school students in a particular town showed that 56 smoke on a regular basis. Find the 95% confidence interval estimating the population percentage for smokers at this high school. Suppose the national average for smokers in high schools is 34.2%. Does it appear that the students in this particular town smoke less than the national average? *Explain why.**Round confidence interval to nearest thousandth.*

Given, Sample size, n = 212 x = 56 Sample proportion, P^ = 56/212 = 0.2642 To find CI, we have below formula, CI = P^ ± Zα/2 * P^1-p^n At 95% confidence level, Zα/2 = Z0.05/2 = 1.96 Therefore, 95% CI = 0.2642±1.96*0.26421-0.2642212 = 0.2642 ± 0.05935 = (0.20485, 0.32355) Therefore, 95% CI : 0.205<p < 0.324

Answered: A random sample of 212 high school…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

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A random sample of 212 high school students in a particular town showed that 56 smoke on a regular basis. Find the 95% confidence interval estimating the population percentage for smokers at this high school. Suppose the national average for smokers in high schools is 34.2%. Does it appear that the students in this particular town smoke less than the national average? Explain why.

Round confidence interval to nearest thousandth.

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