A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 21 28 20 16 13 19 30 22 16 18 19 23 17 20 22 23 Find a 90 percent confidence interval for μ, assuming that the sample is from a normal population. Note: Round your standard deviation answer to 4 decimal places and t-value to 3 decimal places. Round your answers to 3 decimal places.

Q: (b) Test the hypothesis at the a = 0.10 level of significance. Is a mean math score of 530…

A: H0 : ? =523 H1 : ? >523 Population mean = ? = 523 Sample S.D = s =116 Sample size = n…

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A: Given: n = 16 Confidence level = 90%

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A:

Q: How large a sample should be selected to provide a 90% confidence interval with a margin of error of…

A: Given,population standard deviation(σ)=60margin of error(E)=9α=1-0.90=0.1α2=0.05Z0.05=1.645

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Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes).   9 12 22 12…

A: From the given data: x¯=20.25s=5.5678n=16   Degree of freedom=n-1=15

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Q: Find a 95% confidence interval for a mean, µ, where n = 324, x̄ = 2.7, s = .91, and se = .06.

A: Given: n = 324, x̄ = 2.7, s = .91, se = .06.

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Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes).   20 27 24 23…

A: The sample mean is calculated as follows: The standard deviation is calculated as follows:

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A: Given data is36.45,67.90,38.77,42.18,26.72,50.77,39.1,50.03

Q: Round to the fourth H0H0:Select an answer x̄ p̂ μ p  Select an answer =  ≠   HAHA:Select an answer…

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A: Solution

Q: Question 5 The solar energy consumed (in trillion BTU) in the United States by year from 2000 to…

A: Please find the step by step explanation below. Here we should find the 95% confidence interval and…

Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 21 28 20 16…

A: First, we need to calculate the sample mean (x̄), which is the sum of all the sample values divided…

Q: How large a sample should be selected to provide a 95% confidence interval with a margin of error of…

A: Givenconfidence interval(c)=95%margin of error(E)=8standard deviation(σ)=10

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A: Assume that σ is the population standard deviation of volume of soda cans.

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Q: ow large a sample should be selected to provide a 95% confidence interval with a margin of error of…

A: Given Information: Confidence level = 95% = 0.95 Margin of Error = 5 Population standard deviation…

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A: Given data,x=1.1σ=4.9n=51z value at 90% confidence is Zc=1.645

Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 15 12 17 17 14…

A: Given,sample size(n)=16sample mean(x)=17.1875standard deviation(s)=3.6737degrees of…

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A: Sample size n=9 with sample mean  X̄= $522.30 Standard deviations s=$175.00 Population mean μ=…

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A: Solution: Given information: n= 12 Sample size  s= 10.457  weeks  Sample standard deviation  α=0.10…

Q: confidence coefficient to guarantee an increase in the width of the interval?

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A: a) H0: μ = 514 , H1 > 514 ____________________________________

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A: Given that  Sample size n =15 Sample mean =66 Standard deviation =8

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Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 16 20 25 10 18…

A:

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A: n=8p=0.08Let X represent the number of days one elevator is broken during their stay .X~Binomial(n=5…

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A: Given that Sample size n = 22 Sample SD = 0.11 Level of significance = 0.025

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Q: Construct a 90% confidence interval for the population variance.

A: 31

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A: Givenstandard deviation(σ)=15Margin of error(E)=3confidence…