A random sample of 16 pharmacy customers showed the waiting times below (in minutes).   9 12 22 12 22 20 27 20 20 18 26 26 25 21 27 17     Click here for the Excel Data File   Find a 90 percent confidence interval for μ, assuming that the sample is from a normal population. (Round your standard deviation answer to 4 decimal places and t-value to 3 decimal places. Round your answers to 3 decimal places.)    The 90% confidence interval to

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Q: Find a 95% confidence interval for a mean, µ, where n = 324, x̄ = 2.7, s = .91, and se = .06.

A: Given: n = 324, x̄ = 2.7, s = .91, se = .06.

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A: Please find the step by step explanation below. Here we should find the 95% confidence interval and…

Q: You are interested in finding a 90% confidence interval for the average commute that non-residential…

A: Solution: n= 15 Sample size  ∑x=189x=∑xn=18915=12.6 Sample mean…

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Q: Question 2 > You are interested in finding a 90% confidence interval for the mean number of visits…

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Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 15 12 17 17 14…

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Q: are finding a 98% for pnysical therapy patients. The data below show the number of visits for 11…

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Q: How large a sample should be selected to provide a 95% confidence interval with a margin of error of…

A: The confidence level is 95%. Margin of Error, ME = 5 Population Standard deviation, σ=48.   With…