A random sample of 13 health maintenance organizations (HMOS) was selected. For each HMO, the co-payment (in dollars) for a doctor's office visit was recorded. The results are as follows. 9, 11, 6, 10, 6, 12, 11, 11, 7, 10, 6, 9, 10 Send data to calculator Send data to Excel Under the assumption that co-payment amounts are normally distributed, find a 99% confidence interval for the mean co-payment amount in dollars. Then find the lower limit and upper limit of the 99% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.) Lower limit: [) Upper limit:

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A random sample of 13 health maintenance organizations (HMOS) was selected. For each HMO, the co-payment (in dollars) for a doctor's office visit
was recorded. The results are as follows.
9, 11, 6, 10, 6, 12, 11, 11, 7, 10, 6, 9, 10
Send data to calculator
Send data to Excel
Under the assumption that co-payment amounts are normally distributed, find a 99% confidence interval for the mean co-payment amount in dollars.
Then find the lower limit and upper limit of the 99% confidence interval.
Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of
formulas.)
Lower limit: ||
Upper limit:
Transcribed Image Text:A random sample of 13 health maintenance organizations (HMOS) was selected. For each HMO, the co-payment (in dollars) for a doctor's office visit was recorded. The results are as follows. 9, 11, 6, 10, 6, 12, 11, 11, 7, 10, 6, 9, 10 Send data to calculator Send data to Excel Under the assumption that co-payment amounts are normally distributed, find a 99% confidence interval for the mean co-payment amount in dollars. Then find the lower limit and upper limit of the 99% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.) Lower limit: || Upper limit:
Expert Solution
Step 1

Given data : 9, 11, 6, 10, 6, 12, 11, 11, 7, 10, 6, 9, 10

Mean, μ = i xin = 9.076

Standard deviation, σ=i xi2n - (x)2

                                   = 112613 -(9.076)2

                                   = 2.059

 

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