C. A random sample of 100 people is chosen from a large population with an averageweight of 60 kilos and standard deviation of 10 kilos. What is the probability thatthe mean weight of the sample is at least 65 kilos considering the given populationfollows a normal distribution? Show your complete solution.Given:=n =Solution:1. Z= "=2. What is probability that the mean weight of the sample is at least 65 kilos?

From the provided information, Mean (µ) = 60 Standard deviation (σ) = 10 Sample size (n) = 100…

Answered: A random sample of 100 people is chosen…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

We are to estimate the mean of a population, u. The population variance is o. Both the population mean and varíance are unknown. I have twO suggestions as the estimators shown below, A and A2. Tell which one is better. Show all calculations and arguments. Az=
Pls refer to image
A drug company claims that their products’ contaminations never vary by more than 2%. Sample of 5 specimens were tested and the percentages of the purities are recorded as Observation no. 1 2 3 4 5 Percentages (%) 98.8 97.2 98.9 97.7 97.9 a. Do the sample data have enough proof to oppose the manufacturer's claim? (HINT: take the range of 2% equal 4o.) b. Find a 90% confidence interval for o?.
touch ".llE 55% D14:52 Question Measurements for the length and width of a rectangular plastic covers for CDs are Tounded to the nearest mm (so they are discrete). Let X denote the length and Y dente the width. The possible values of X are 129, 130, and 131 mm. The possible values of Y are 15 and 16 mm. The joint distribution is given by the following table X-length 129 130 131 Y=width 15 0.12 0.42 006 16 0.08 0.28 0.04 The probability that a CD cover has width of 16 mm knowing that it has a length of 131 mm is O 0.13 O 0.2 O 0.4 O 0.08
Q scores are normally distributed with μ = 100 and σ = 15. Find the IQ score separatingthe highest 4% of all scores.
Solve the given problem, Find z, z value (area), graph the normal curve and the n. 1. the mean weight of 500 male students at a certain college is 151 lb and the standard deviation is 15 lb. Assuming that the weights are normally distributed, find how many students weighs: a. between 120 and 155lbs b. more than 185 lbs
Plot the appraisal price in dollars that can be paid for combined lease bonus and speculative drilling cost using the following risk: 1,5, and 10 %. The prospect is a 80- acre tract, pay thickness is 100 ft. The probability of dry hole is set at 50%. If the well is successful, recovery in bbls per acre-ft may be as low as 100 to as high as 200, with most probable recovery being 150 bbl/acre-ft. Operating profit may be taken as $ 3 per barrel. Completion costs for a successful well will exceed the cost of a dry well by $40,000. Assume the exploration budget is 0, 3, 6 and 10 MM dollars
You are given that X follows a Weibull distribution where alpha = 2.3 beta = 17.4 What is the value of the the 60th percentile of this distribution?
A population of scores has a mean of µ=89, a median of 87 and a mode of 85. What is the most likely shape for the population distribution? Symmetrical Positively skewed Negative skewed It cannot be determined from the information given O O
A population of N = 25 scores has ΣX = 40 and ΣX2= 120. For this population, what is the value of SS (sum of squared deviations)? Select one: a. 20 b. 56 c. 60 d. 84
1:37 PM Wed Apr 21 * 72% 88 Q Stats Exam •.. Untitled Notebook (1) Stats Exam 37. The manager of Green Valley medical center claims that the median number of patients seen by doctors who work at the center is 85. To test this claim, 20 days are randomly selected and the number of patients seen is recorded as shown. At a=0.1, test the claim. (Use sign test) 86 82 90 88 85 85 94 93 69 61 89 90 91 94 78 85 71 77 69 77
State the conclusion based on the results of the test. The mean of the pressure required to open a certain valve is known to be u = 6.7 psi. Due to changes in the manufacturing process, the quality-control manager feels that the average pressure has changed. The null hypothesis was rejected. Choose the correct answer below. O A. The mean of the pressure has not changed. O B. There is not sufficient evidence that the mean of the pressure required to open a certain valve has changed. O C. There is not sufficient evidence that the mean of the pressure required to open a certain valve has not changed. O D. The mean of the pressure has changed. O E. There is sufficient evidence that the mean of the pressure required to open a certain valve has changed. O F. There is sufficient evidence that the mean of the pressure required to open a certain valve has not changed.

Recommended textbooks for you

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

SEE MORE TEXTBOOKS