A radioactive substance has a half-life of one week. In other words, at the end of every week the level of radioactivity is half of its value at the beginning of the week. The initial level of radioactivity is 20 counts per second. a) Find the formula that gives the radioactivity in terms of time (t). b) Find the radioactivity left after three weeks.

Algebra and Trigonometry (6th Edition)
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Author:Robert F. Blitzer
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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A radioactive substance has a half-life of one
week. In other words, at the end of every week
the level of radioactivity is half of its value at
the beginning of the week. The initial level of
radioactivity is 20 counts per second.
a) Find the formula that gives the radioactivity
in terms of time (t).
b) Find the
radioactivity left after three weeks.
Formula:
y = a(bji or y = a(1 + r)i
Where,
y is the population after x time;
a is the initial amount
bis the growth factor which is equal to 1+r
r is the rate growth as decimal
x is the units of time
T is the time when the quantity doubled (growth
factor)
Transcribed Image Text:A radioactive substance has a half-life of one week. In other words, at the end of every week the level of radioactivity is half of its value at the beginning of the week. The initial level of radioactivity is 20 counts per second. a) Find the formula that gives the radioactivity in terms of time (t). b) Find the radioactivity left after three weeks. Formula: y = a(bji or y = a(1 + r)i Where, y is the population after x time; a is the initial amount bis the growth factor which is equal to 1+r r is the rate growth as decimal x is the units of time T is the time when the quantity doubled (growth factor)
y = a(b)f or y = a(1 + r)i
Transcribed Image Text:y = a(b)f or y = a(1 + r)i
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