A radio station claims that the amount of advertising per hour of broadcast time has an average of 12 minutes and a standard deviation equal to 2.4 minutes. You listen to the radio station for 1 hour, at a randomly selected time, and carefully observe that the amount of advertising time is equal to 5 minutes. Calculate the z-score for this amount of advertising time. O z= 0.22 O z= -2.92 O z= -0.22 O z= 2.92

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A radio station claims that the amount of advertising per hour of broadcast time has an average of 12 minutes and a standard deviation equal to 2.4 minutes. You listen to the radio
station for 1 hour, at a randomly selected time, and carefully observe that the amount of advertising time is equal to 5 minutes. Calculate the z-score for this amount of advertising time.
O z = 0.22
O z = -2.92
O z = -0.22
O z = 2.92
A Moving to another question will save this response.
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Transcribed Image Text:Save Answer Provide an appropriate response. A radio station claims that the amount of advertising per hour of broadcast time has an average of 12 minutes and a standard deviation equal to 2.4 minutes. You listen to the radio station for 1 hour, at a randomly selected time, and carefully observe that the amount of advertising time is equal to 5 minutes. Calculate the z-score for this amount of advertising time. O z = 0.22 O z = -2.92 O z = -0.22 O z = 2.92 A Moving to another question will save this response. <Question 4 of 9 9:38 AM 3/10/2021 PrtScn Home End 411 96 8 E R Y F J K Alt
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