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A radio active element (x) has a half-life of 38 hours. Initially, x= xo. Determine the amount of radio active element at any time, t. I= Toe 38 I= 1₂e x= x₂e x = Ce tln(0.5) x = Ce -In (0.1) 38 - In (0.5) 38 t In (0.5) 38 tln(0.5) 38 tl (0.1) I=I₂e 38

A radio active element (x) has a half-life of 38 hours. Initially, x= xo. Determine the amount of radio active element at any time, t. I= Toe 38 I= 1₂e x= x₂e x = Ce tln(0.5) x = Ce -In (0.1) 38 - In (0.5) 38 t In (0.5) 38 tln(0.5) 38 tl (0.1) I=I₂e 38

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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NUMBER 8

Topic: Differential Equations (Engineering)
1. Follow the rule correctly. 
2. Solve the asked problem in a step-by-step procedure
3. Kindly encircle the final answer. 
4. Double-check your solutions because we need them for our review.

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Note: If it is true or false, kindly explain why it was true or vice versa.

A radio active element (x) has a half-life of 38 hours. Initially, x= xo. Determine the amount of radio active element at any time, t. I= Toe 38 I= 1₂e x= x₂e x = Ce tln(0.5) x = Ce -In (0.1) 38 - In (0.5) 38 t In (0.5) 38 tln(0.5) 38 tl (0.1) I=I₂e 38
Transcribed Image Text:A radio active element (x) has a half-life of 38 hours. Initially, x= xo. Determine the amount of radio active element at any time, t. I= Toe 38 I= 1₂e x= x₂e x = Ce tln(0.5) x = Ce -In (0.1) 38 - In (0.5) 38 t In (0.5) 38 tln(0.5) 38 tl (0.1) I=I₂e 38
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