A racecar accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. Determine the acceleration of the car. (Use the kinematic equation of particles).
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- A blue car travels down a straight road at a constant speed of 21.7 m/s. As they pass a red car, initially stopped on the side of the road, the red car speeds up at a rate of 2.12 m/s2. How much distance (in m) does the blue car travel before the red car overtakes the blue car?Two cars are driving, car 1 has initial position -3500m, initial velocity -55m/s and acceleration +1.25m/s2, car 2 has initial position +4100m, initial velocity -35 m/s and acceleration +0.75m/s2; a) How much time until they collide? b) What is the x location where they collide, and the final velocity of each car?Your answer is partially correct. In the figure here, a red car and a green car move toward each other in adjacent lanes and parallel to an x axis. At time t = 0, the red car is at x₁ = 0 and the green car is at x§ = 225 m. If the red car has a constant velocity of 26.0 km/h, the cars pass each other at x = 44.1 m. On the other hand, if the red car has a constant velocity of 52.0 km/h, they pass each other at x = 76.6 m. What are (a) the initial velocity and (b) the (constant) acceleration of the green car? Include the signs. (a) Number (b) Number 61.0 4.14 Red car Unit Unit km/h m/s^2 Green car x
- Ahmed and Khalid are having a 100m race from start to finish. Ahmed gives Khalid a 25m head start (he waits until Khalid is 25m away before starting) .Khalid travels at a constant velocity of 5 m/s. Assuming that Ahmed accelerates uniformly from rest at 0.75 m/s2, does he pass Khalid before the finish line? If so, where? If not, how much longer does Khalid take to finish? (explain your reasoning)I had a dream last night that I was chased by my teddy bear. In my dream, I was sleepwalking at a constant velocity of 60ft/sec. At exactly 4:00 am I noticed my teddy bear standing 1000 feet behind me. At that instant I began to accelerate at 10 ft/sec/sec and the teddy bear began to accerlate after me at 12 ft/sec/sec. At the moment the bear caught up to me, I woke from my dream in a cold sweat. To the nearest second, What time was this?A car, initially at rest, accelerates at a constant rate, 3.36 m/s2 for 32.6 seconds in a straight line. At this time, the car decelerates at a constant rate of -2.00 m/s2, eventually coming to rest. How much distance (in meters) did the car travel during the deceleration portion of the trip?
- The velocity of a particle is given by v(t) =t² – 2t. The position of the particle at the time t = 0 is S(0) = 0. 1. Find a formula for the position S(t) at time t. 2. Find the displacement of the object on [0,3]. 3. Find the total distance traveled by the particle on [0,3].A blue car travels down a straight road at a constant speed of 18.8 m/s. As they pass a red car, initially stopped on the side of the road, the red car speeds up at a rate of 1.77 m/s2. How much distance (in m) does the red car travel before it overtakes the blue car?Can an object have a negative acceleration and be speeding up? If so, describe a possible physical situation and a corresponding coordinate system. If not, explain why not.