Physics Question #23 **Problem 23: Motion of Two Motorcycles****Scenario:**Two motorcycles are traveling due east but have different initial velocities. Four seconds later, they are moving at the same velocity.- During this four-second interval: - Motorcycle A has an average acceleration of 2.0 m/s² due east. - Motorcycle B has an average acceleration of 4.0 m/s² due east.**Question:***By how much did the speeds differ at the beginning of the four-second interval, and which motorcycle was moving faster initially?***Analysis:**1. Let's denote the initial velocities of motorcycle A and motorcycle B as \( v_{A_0} \) and \( v_{B_0} \) respectively.2. After four seconds, they have reached the same velocity, say \( v_f \).For Motorcycle A:\[v_f = v_{A_0} + (2.0 \, \frac{m}{s^2}) \times 4 \, s\]For Motorcycle B:\[v_f = v_{B_0} + (4.0 \, \frac{m}{s^2}) \times 4 \, s\]Since both reach the same final velocity \( v_f \):\[v_{A_0} + 8 = v_{B_0} + 16\]Therefore:\[v_{B_0} = v_{A_0} - 8\]**Conclusion:**Motorcycle A's initial speed was faster by 8 m/s compared to Motorcycle B's initial speed.

Name: Physics Question #23 **Problem 23: Motion of Two Motorcycles****Scenar
Uploaded: 2024-03-05T11:56:34.000Z
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Description: Physics Question #23 **Problem 23: Motion of Two Motorcycles****Scenario:**Two motorcycles are traveling due east but have different initial velocities. Four seconds later, they are moving at the same velocity.- During this four-second interval: - M

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**23. Two motorcycles are traveling due east with different velocities. However, four seconds later, they have the same velocity. During this four-second interval, cycle A has an average acceleration of 2.0 m/s² due east, while cycle B has an average acceleration of 4.0 m/s2 due east. By how much did the speeds differ at the beginning of the four-second inter- val, and which motorcycle was moving faster?