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A pulley has a tangential velocity of 75 fpm. If pulley diameter is 10 inches, find the speed of the speed. A. 24.34 rpm B. 28.65 rpm C. 34.22 rpm D. 32.34 rpm Please solve the Problem elaborately. Your solution will be use as reference for my studies. Thank you so much your work will be appreciated much!

A pulley has a tangential velocity of 75 fpm. If pulley diameter is 10 inches, find the speed of the speed. A. 24.34 rpm B. 28.65 rpm C. 34.22 rpm D. 32.34 rpm Please solve the Problem elaborately. Your solution will be use as reference for my studies. Thank you so much your work will be appreciated much!

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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A pulley has a tangential velocity of 75 fpm. If pulley diameter is 10 inches, find the speed of the speed. A. 24.34 rpm B. 28.65 rpm C. 34.22 rpm D. 32.34 rpm Please solve the Problem elaborately. Your solution will be use as reference for my studies. Thank you so much your work will be appreciated much!
Esquare y 80. fons Machine Elements 1. Cylinders Rolling in opposite direction: A. Tangential speed V = Va = n D, N == D, Na B. Relation of diameter and speed D. N. = D. Na Speed Ratio = Speed of Driver Speed of the Driven C D. Center Distance- R, + R, D, + D2 2 2. Cylinders Rolling in the same direction A. Tangential speed VVn D, N = D, N, D: N = D. Na B. Relation of diameter and speed Speed of Driver Speed of the Driven . C. Speed Ratio = D. Center Distance = R, -R,- D-D, 2 Stresses 1. Stress (S) = a total resistance that a material offers to an applied load, Ibin, kg/cm, KN/m? 2. Ultimate stress (S.) - is the stress that would cause failure 3. Yield stress(S,) - maximum stress without causing deformation 4. Allowable stress(Sa) = Ultimate stress/Factor of Safety 5. Design stress(S.) - stress used in determining the size of a member. S= or S= where: FS - factor of safety S = 1 1. Tensile Stress (S) For solid circular cross-section: A = D For hollow circular cross-section: A = (D, -D) For rectangular cross-section: A = base x height = b xh 2. Compressive Stress(S.)S. 3. Shearing Stress(S.) A. For single bolt of rivet needed to join to plates together. S, = For single rivet: A= z4 D For double riveted joint: A = 2(m/4 D) where: B. Shearing due to punching of hole. S= where A DI (for punching a hole) A = 4St (for square hole) Where: S= length of side of t= plate thickness Where: d= hole diameter, in 4. Bearing Stress(S) S, F IA C. Pressure needed to punch a hole, F: F=dxtx 80, tons t= thickness, in where: A= DL She a wea 5. Factor of safety(FS) a. Based on yield strength FS = S, /S. b. Based on ultimate strength FS = s./ Sa 6. Torsional Shear Stress(S.) Projected Area where: J = polar moment of inertia = T D' /32 (for solid shaft) T= torque c - distance from neutral axis to the farthest fiber Cr (for circular cross section) 7. Bending Stress(S) d- diameter 6 M S- For rectangular beam S = b h where: M = moment C distance of farthest fiber from neutral axis I- moment of inertia about the neutral axis = bh/12 (for rectangular cross section) Z = section modulus = c S 8. Strain and Elongation Strain = ! Stress E. Stress . FL Strain Y= FL . AE = L- original length S stress where: y- elongation due to applied load F force A area 9. Thermal Elongation; Stresses y = kL (t - t:) s = EL = kE (t - t) where: k = coefficient of thermal expansion, m/m-C For steel k- 6.5 x 104 inin-F- 11.7 x 104 m/m-C E = 30 x 10 psi Relation betwoen shearing and tensile stress based on theory of failure: Swa- S Suma- Sy 12 10. Variable Stress 1. S, . FS S, S S, - yield point S = mean stress where: FS = factor of safety S. endurance limit Smax +Sn S. = variable component stress Sen minimum stress 11. Poisson's Ratio(u) = is the ratio of lateral unit deformation to axial unit deformation. S maximum stress where: G = shear modulus of elasticity E- strain AE F 2G Lateral Strain EyE Longitudin al Strain .Ex Wa-W E, -4
Transcribed Image Text:Esquare y 80. fons Machine Elements 1. Cylinders Rolling in opposite direction: A. Tangential speed V = Va = n D, N == D, Na B. Relation of diameter and speed D. N. = D. Na Speed Ratio = Speed of Driver Speed of the Driven C D. Center Distance- R, + R, D, + D2 2 2. Cylinders Rolling in the same direction A. Tangential speed VVn D, N = D, N, D: N = D. Na B. Relation of diameter and speed Speed of Driver Speed of the Driven . C. Speed Ratio = D. Center Distance = R, -R,- D-D, 2 Stresses 1. Stress (S) = a total resistance that a material offers to an applied load, Ibin, kg/cm, KN/m? 2. Ultimate stress (S.) - is the stress that would cause failure 3. Yield stress(S,) - maximum stress without causing deformation 4. Allowable stress(Sa) = Ultimate stress/Factor of Safety 5. Design stress(S.) - stress used in determining the size of a member. S= or S= where: FS - factor of safety S = 1 1. Tensile Stress (S) For solid circular cross-section: A = D For hollow circular cross-section: A = (D, -D) For rectangular cross-section: A = base x height = b xh 2. Compressive Stress(S.)S. 3. Shearing Stress(S.) A. For single bolt of rivet needed to join to plates together. S, = For single rivet: A= z4 D For double riveted joint: A = 2(m/4 D) where: B. Shearing due to punching of hole. S= where A DI (for punching a hole) A = 4St (for square hole) Where: S= length of side of t= plate thickness Where: d= hole diameter, in 4. Bearing Stress(S) S, F IA C. Pressure needed to punch a hole, F: F=dxtx 80, tons t= thickness, in where: A= DL She a wea 5. Factor of safety(FS) a. Based on yield strength FS = S, /S. b. Based on ultimate strength FS = s./ Sa 6. Torsional Shear Stress(S.) Projected Area where: J = polar moment of inertia = T D' /32 (for solid shaft) T= torque c - distance from neutral axis to the farthest fiber Cr (for circular cross section) 7. Bending Stress(S) d- diameter 6 M S- For rectangular beam S = b h where: M = moment C distance of farthest fiber from neutral axis I- moment of inertia about the neutral axis = bh/12 (for rectangular cross section) Z = section modulus = c S 8. Strain and Elongation Strain = ! Stress E. Stress . FL Strain Y= FL . AE = L- original length S stress where: y- elongation due to applied load F force A area 9. Thermal Elongation; Stresses y = kL (t - t:) s = EL = kE (t - t) where: k = coefficient of thermal expansion, m/m-C For steel k- 6.5 x 104 inin-F- 11.7 x 104 m/m-C E = 30 x 10 psi Relation betwoen shearing and tensile stress based on theory of failure: Swa- S Suma- Sy 12 10. Variable Stress 1. S, . FS S, S S, - yield point S = mean stress where: FS = factor of safety S. endurance limit Smax +Sn S. = variable component stress Sen minimum stress 11. Poisson's Ratio(u) = is the ratio of lateral unit deformation to axial unit deformation. S maximum stress where: G = shear modulus of elasticity E- strain AE F 2G Lateral Strain EyE Longitudin al Strain .Ex Wa-W E, -4
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