A publisher wants to estimate the mean length of time (in minutes)all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes standard deviation is 2.2 minutes and that the population of times is normally distributed . 6 8 6 12 7 6 10 11 11 8 8 9 6 10 10 Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient use technology to construct the confidence intervals. The 90% confidence interval is _________, __________ (round to one decimal place) The 99% confidence interval is _________, __________ (round to one decimal place) Which interval is wider? The 99% confidence interval. Or The 90% confidence interval
Section 6.1 (please help with TI-84 commands if possible)
A publisher wants to estimate the
6 8 6 12 7 6 10 11 11 8 8 9 6 10 10
Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient use technology to construct the confidence intervals.
The 90% confidence interval is _________, __________ (round to one decimal place)
The 99% confidence interval is _________, __________ (round to one decimal place)
Which interval is wider?
The 99% confidence interval.
Or
The 90% confidence interval
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