A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes o is 2.2 minutes and that the population of times is normally distributed. 11 8 11 11 9 12 7 7 7 10 12 10 12 Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals. The 90% confidence interval is ( | D. (Round to one decimal place as needed.)

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A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and
obtains the results below. From past studies, the publisher assumes o is 2.2 minutes and that the population of times is normally distributed.
11
8
11
11
9
12
7
7
7
10
12
10
12
Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals.
The 90% confidence interval is ( | D. (Round to one decimal place as needed.)
Transcribed Image Text:A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes o is 2.2 minutes and that the population of times is normally distributed. 11 8 11 11 9 12 7 7 7 10 12 10 12 Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals. The 90% confidence interval is ( | D. (Round to one decimal place as needed.)
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